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Dima020 [189]
3 years ago
7

Compare and contrast vertical and lateral acceleration

Physics
1 answer:
Drupady [299]3 years ago
7 0
The answer to the question asked  above is vertical acceleration is the acceleration of a body in a vertical path either up or down, while lateral acceleration is the acceleration of body in a side manner either left of right.


Hope my answer would be a great help for you.    If you have more questions feel free to ask here at Brainly.
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A certain field line diagram illustrates the electric field due to three particles that carry charges 5.0 μC, -3.0 μC, and -2.0
4vir4ik [10]

Answer:

6

Explanation:

Number of lines emanate from + 5 micro coulomb is 15 .

They terminates at negative charges that means at - 3 micro coulomb and - 2 micro Coulomb.

the electric field lines terminates at - 3 micro Coulomb and - 2 micro Coulomb is in the ratio of 3 : 2.

So the lines terminating at - 3 micro coulomb

                                    = \frac{3}{5}\times 15 = 9

So the lines terminating at - 2 micro coulomb

                                    = \frac{2}{5}\times 15 = 6

So, the number of filed lines terminates at - 2 micro Coulomb are 6.

4 0
3 years ago
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Oksanka [162]

Answer:

I believe the answer is B.)

6 0
2 years ago
The energy due to Earth pulling down on an object is called ___.
Slav-nsk [51]

Gravity is the energy due to Earth pulling down on an object.

6 0
3 years ago
I need this ASAP<br> Name the three types of perodic maintenance with examples each.
artcher [175]

Predictive maintenance - vibration analysis.

Condition-based maintenance - monitoring pressure reading on Equipment with water systems.

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3 0
3 years ago
A skateboarder traveling at 4.45 m/s can be stopped by a strong force in 1.82 s and by a weak force in 5.34 s.
ANTONII [103]

1) Impulse: -238.5 kg m/s

2) Strong force: -131.1 N, weak force: -44.7 N

Explanation:

1)

The impulse exerted on an object is equal to the change in momentum of the object itself.

Mathematically:

I=\Delta p=m(v-u)

where

m is the mass of the object

u is the initial velocity

v is the final velocity

For the skateboarder in this problem, we have:

m = 53.6 kg

u = 4.45 m/s

v = 0 (it comes to a stop)

Therefore, the impulse is

I=(53.6)(0-4.45)=-238.5 kg m/s

Where the negative sign indicates that the direction is opposite to the motion of the object.

2)

The impulse is also equal to the product between the force applied and the duration of the collision:

I=F\Delta t

where

I is the impulse

F is the average force

\Delta t is the time during which the force is applied

The strong force is applied in a time of

\Delta t = 1.82 s

Therefore this force is

F=\frac{I}{\Delta t}=\frac{-238.5}{1.82}=-131.1 N

The  weak force is applied in a time of

\Delta t = 5.34 s

So this force is

F=\frac{I}{\Delta t}=\frac{-238.5}{5.34}=-44.7 N

Learn more about impulse:

brainly.com/question/9484203

#LearnwithBrainly

6 0
3 years ago
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