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Vilka [71]
3 years ago
12

Pick one option:

Chemistry
1 answer:
Dmitry [639]3 years ago
4 0

Answer:

Li⁺

Explanation:

Li⁺ ions has a noble gas electron configuration because it resembles that of He.

To have a noble configuration, electrons in the outermost shell must completely fill their respective orbitals.

Li⁺ is an ion that has lost one electron from the usual number of 3 thereby remaining 2 electrons.

 The electronic configuration is given as;

         Li⁺       1s²

The S orbital can hold a maximum number of just two electrons.

     Helium atom has two electrons with electronic configuration of  1s²

Therefore      Li⁺   =    1s²    =    He

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Zinc sulfate is a 2-ion electrolyte,
Gekata [30.6K]

<u>Answer:</u> The value of <em>i</em> is 1.4 and 40% dissociation of 100 particles of zinc sulfate will yield 60 undissociated particles.

<u>Explanation:</u>

The equation used to calculate the Vant' Hoff factor in dissociation follows:

\alpha =\frac{i-1}{n-1}

where,

\alpha = degree of dissociation = 40% = 0.40

i = Vant' Hoff factor

n = number of ions dissociated = 2

Putting values in above equation, we get:

0.40=\frac{i-1}{2-1}\\\\0.40=i-1\\\\i=1.4

The equation used to calculate the degee of dissociation follows:

\alpha =\frac{\text{Number of particles dissociated}}{\text{Total number of particles taken}}

Total number of particles taken = 100

Degree of dissociation = 40% = 0.40

Putting values in above equation, we get:

0.40=\frac{\text{Number of particles dissociated}}{100}\\\\\text{Number of particles dissociated}=(0.40\times 100)=40

This means that 40 particles are dissociated and 60 particles remain undissociated in the solution.

Hence, 40% dissociation of 100 particles of zinc sulfate will yield 60 undissociated particles.

7 0
3 years ago
What are the products of this chemical equation? HCl(aq) + NaOH(aq) →
rusak2 [61]
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Based on the nebular theory of the solar system formation, explain how our solar system is formed.
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6 0
3 years ago
What is the ph of a solution of 0.550 m k2hpo4, potassium hydrogen phosphate?
Solnce55 [7]
We assume that we have Ka= 4.2x10^-13 (missing in the question)
and when we have this equation:
H2PO4 (-) → H+  + HPO4-
and form the Ka equation we can get [H+]:
Ka= [H+] [HPO4-] / [H2PO4] and we have Ka= 4.2x10^-13 & [H2PO4-] = 0.55m
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PH= -㏒[H+]
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