1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Damm [24]
3 years ago
7

How do you if a reaction is exthermic

Chemistry
1 answer:
Artist 52 [7]3 years ago
3 0

Answer:

To know if a reaction/experiment is exothermic or endothermic depends on the temperatures of the two liquids you are trying to mix. First before mixing your liquids take the temperature of both of them and write it down. then mix both liquids together to get your reaction and take the temperature of both mixed together. write it down. Did the temperature of your liquids increase or decrease? this question will determine weather the reaction was endothermic or exothermic. Endothermic meaning the temperature got cooler and Exothermic meaning the temperature got hotter/warmer

EX. | starting temperature- 72 F | ending temperature- 82 F | Exothermic

EX 2. | starting temperature- 72 F | ending temperature- 69 F | Endothermic

Explanation: I hope this helped you :)

You might be interested in
4AI+30 2 > 2AI2O3 What id the chemical reaction?
vesna_86 [32]
This is a combination reaction.  Look at the 2 elements on left and a compound on the right.
7 0
3 years ago
if the density of a bar of gold is 19.3g/cm^3and you cut it into four pieces , what is its density of each piece of gold
AlladinOne [14]
Density is an intrinsic property, so it is independent of the amount of substance present: one gold coin would have the same density as a solid gold boulder.

So if the density of gold is 19.3 g/cm³, the density of a bar of gold and the pieces into which the bar is cut would all be 19.3 g/cm³.
4 0
3 years ago
A steel cylinder of oxygen is being store in a room at 25.0 °C under a pressure of 1250 atm. What pressure would be exerted by t
Rudik [331]

Answer:

P₂ = 1312.88 atm

Explanation:

Given data:

Initial temperature = 25°C

Initial pressure = 1250 atm

Final temperature = 40°C

Final pressure = ?

Solution:

Initial temperature = 25°C (25+273.15 = 298.15 K)

Final temperature = 40°C ( 40+273.15 = 313.15 k)

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

1250 atm / 298.15 K = P₂/313.15 K

P₂ = 1250 atm × 313.15 K / 298.15 K

P₂ = 391437.5 atm. K /298.15 K

P₂ = 1312.88 atm

6 0
3 years ago
Wine is 13 % alcohol by volume. How many milliliters of alcohol are in a 0.900-L bottle of wine?
AURORKA [14]
13% of 0.900 is 0.117
there are 0.117 milliliters of alcohol in a 0.900-L bottle of wine.
3 0
3 years ago
Read 2 more answers
URGENT is... Mg(ClO3)2
stiv31 [10]

That's a ionic compound because it has a metal and polyatomic parts within the chemical formula.

6 0
3 years ago
Read 2 more answers
Other questions:
  • Atoms are composed of a central nucleus which is surrounded by orbiting
    5·1 answer
  • How can you separate a mixture of dry materials
    8·1 answer
  • What is the correct way to write .00095 in scientific notation
    13·2 answers
  • What is the pH of a substance that has a hydrogen ion concentration of<br> 8.8x10^(-5) M? *
    7·1 answer
  • The free energy for the oxidation of glucose to CO2 and water is -686 kcal/mol, and the free energy for the reduction of NAD+ to
    11·1 answer
  • Complete the chart
    15·1 answer
  • Determine the mass of hydrogen chloride needed to react completely with 12.8 g of aluminum to produce aluminum chloride and hydr
    10·1 answer
  • This is the last week of school for me and i need help pleaseee !!
    7·1 answer
  • Grade7science
    10·1 answer
  • As a whole, plants tend to release more oxygen than carbon dioxide into the environment, but the ratios of gases differ at vario
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!