2 near the middle
between ultraviolet and infared
The answer would be 22.50cal
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Answer:
ΔV = 0.98 L
Explanation:
First, we will calculate the increased volume using Charles' Law:

where,
V₁ =initial volume = 18.9 L
V₂ = final volume = ?
T₁ = initial temperature = 15°C + 273 = 288 k
T₂ = final temperature = 30°C + 273 = 303 k
Therefore,

V₂ = 19.88 L
Now, we calculate the change in volume:
ΔV = V₂ - V₁ = 19.88L - 18.9 L
<u>ΔV = 0.98 L</u>
This is the volume of gasoline that will spill out.