Question

A sample of argon gas occupies 105 mL at 0.871 atm. If

Answer 1

Answer:

1. final pressure = 0.259atm

2. 196.84mmHg

Explanation:

Using Boyle's law of equation

P1V1 = P2V2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

V1 = initial volume (mL)

V2 = final volume (mL)

According to the information given in this question:

V1 = 105mL

V2 = 352mL

P1 = 0.871atm

P2 = ?

Using P1V1 = P2V2

P2 = P1V1/V2

P2 = 0.871 × 105/352

P2 = 91.455/352

P2 = 0.2598

P2 = 0.259atm

To convert 0.259atm of the gas into mmHg, we multiply the value in atm by 760.

Hence, 0.259 × 760

= 196.84mmHg