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Alla [95]
3 years ago
10

A sample of argon gas occupies 105 mL at 0.871 atm. If

Chemistry
1 answer:
qwelly [4]3 years ago
6 0

Answer:

1. final pressure = 0.259atm

2. 196.84mmHg

Explanation:

Using Boyle's law of equation

P1V1 = P2V2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

V1 = initial volume (mL)

V2 = final volume (mL)

According to the information given in this question:

V1 = 105mL

V2 = 352mL

P1 = 0.871atm

P2 = ?

Using P1V1 = P2V2

P2 = P1V1/V2

P2 = 0.871 × 105/352

P2 = 91.455/352

P2 = 0.2598

P2 = 0.259atm

To convert 0.259atm of the gas into mmHg, we multiply the value in atm by 760.

Hence, 0.259 × 760

= 196.84mmHg

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g n the Ideal Gas Law lab, how is the temperature of the hydrogen gas determined? Select one: The pressure of the gas is determi
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Answer:

The volume of the gas is determined, which will allow you to calculate the temperature.

Explanation:

According to Charles law; the volume of a given mass of an ideal gas is directly proportional to its temperature at constant pressure.

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Answer:

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Explanation:

Step 1: Given data

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Step 2: Calculate the temperature change

ΔT = 80 K - 45 K = 35 K

Step 3: Calculate the heat required (Q)

We will use the following expression.

Q = c × m × ΔT

Q = 0.231 J/kg.K × 12 kg × 35 K = 97 J

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