Which of the following causes objects to orbit the Sun?

Physics

2 answers:

algol [13]2 years ago

7 0

B. The suns gravity

hope this helps

Gekata [30.6K]2 years ago

4 0

In order for an object to be in orbit around a larger object. The larger object my exert its gravity on the smaller object. Like a planet around the sun, or a satellite around the Earth or Moon. This answer is B

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The function H(t) = -16t^2 + vt + s shows the height H (t), in feet, of a projectile launched vertically from s feet above the g

Reptile [31]

H(t) = -16t^2 + vt + s
Part A:
Using the given data:

H(t)= -16*t² + 60*t + 82;

Part B:
Put H(t)=0
0= -16*t² + 60*t + 82;
Use the quadratic formula to find t.
See the attachment...'t' is replaced with 'x'.

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2 years ago

A small car of mass m and a large car of mass 4m drive along a highway at constant speeds VS and VL. They approach a curve of ra

Arte-miy333 [17]

Answer:

$v_S=\sqrt{2}v_L$

Explanation:

The acceleration experimented while taking a curve is the centripetal acceleration $a=\frac{v^2}{r}$ . Since $a_S=2a_L$ , we have that: $\frac{v_S^2}{r_S}=\frac{2v_L^2}{r_L}$

They take the same curve, so we have: $r_S=r_L=R$

Which means: $v_S^2=2v_L^2$

And finally we obtain: $v_S=\sqrt{2}v_L$

4 0

3 years ago

Which of the following is not an example of centripetal acceleration?

Amanda [17]

An apple falling to the ground is not an example of centripetal acceleration.

5 0

2 years ago

A hot air balloon is on the ground, 200 feet from an observer. The pilot decides to ascend at 100 ft/min. How fast is the angle

liq [111]

Answer:

0.0031792338 rad/s

Explanation:

$\theta$ = Angle of elevation

y = Height of balloon

Using trigonometry

$tan\theta=y\dfrac{y}{200}\\\Rightarrow y=200tan\theta$

Differentiating with respect to t we get

$\dfrac{dy}{dt}=\dfrac{d}{dt}200tan\theta\\\Rightarrow \dfrac{dy}{dt}=200sec^2\theta\dfrac{d\theta}{dt}\\\Rightarrow 100=200sec^2\theta\dfrac{d\theta}{dt}\\\Rightarrow \dfrac{d\theta}{dt}=\dfrac{100}{200sec^2\theta}\\\Rightarrow \dfrac{d\theta}{dt}=\dfrac{1}{2}cos^2\theta$