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3 years ago

Which of the following causes objects to orbit the Sun?

Physics

2 answers:

algol [13]3 years ago

7 0

B. The suns gravity

hope this helps

Gekata [30.6K]3 years ago

4 0

In order for an object to be in orbit around a larger object. The larger object my exert its gravity on the smaller object. Like a planet around the sun, or a satellite around the Earth or Moon. This answer is B

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Which standing wave has four antibodies?

frez [133]

Answer:

Term (symbol) Meaning

Standing wave Waves which appear to be vibrating vertically without traveling horizontally. Created from waves with identical frequency and amplitude interfering with one another while traveling in opposite directions.

Node Positions on a standing wave where the wave stays in a fixed position over time because of destructive interference.

Antinode Positions on a standing wave where the wave vibrates with maximum amplitude.

Fundamental frequency Lowest frequency of a standing wave that has the fewest number of nodes and antinodes.

Harmonic A standing wave that is a positive integer multiple of the fundamental frequency.

Explanation:

7 0

4 years ago

A car drives 100 km north, 50 km east, then 10 km south. What is the car's displavement?

Over [174]

Answer:

$\sqrt{ ({40}^{2} } + {50}^{2} ) = \sqrt{(1600 + 2500)} = \sqrt{4100} = 64.03$

6 0

4 years ago

Two trains are blowing their whistles. The first train is stationary, and the

Liono4ka [1.6K]

Answer:

A I think

Pls Mark Brainiest, I'm trying to become Virtuoso

3 0

3 years ago

A 65.0-kg woman steps off a 10.0-m diving platform and drops straight down into the water. 1) If she reaches a depth of 3.20 m,

timurjin [86]

Answer:

F=2627.6N

Explanation:

The work done by this resistive force while traveling a distance <em>d</em> underwater would be:

$W=F.d=-Fd$

where the minus sign appears because the force is upwards and the displacement downwards.

This work is equal to the change of mechanical energy. At the diving plataform and underwater, when she stops moving, the woman has no kinetic energy, so all can be written in terms of her total change of gravitational potential energy:

$W=\Delta E=U_f-U_i=mgh_f-mgh_i=mg(h_f-h_i)$

Putting all together:

$F=-\frac{W}{d}=-\frac{mg(h_f-h_i)}{d}=-\frac{(65kg)(9.8m/s^2)(-3.2m-10m)}{3.2m}=2627.6N$

7 0

3 years ago

A hydrogen atom in a galaxy moving with a speed of 6.65×106 m/???? away from the Earth emits light with a wavelength of 5.13×10−

Mumz [18]

Answer:

The observed wavelength on Earth from that hydrogen atom is $5.24\times 10^{-7}\ m$ .

Explanation:

Given that,

The actual wavelength of the hydrogen atom, $\lambda_a=5.13\times 10^{-7}\ m$

A hydrogen atom in a galaxy moving with a speed of, $v=6.65\times 10^6\ m/s$

We need to find the observed wavelength on Earth from that hydrogen atom. The speed of galaxy is given by :

$v=c\times \dfrac{\lambda_o-\lambda_a}{\lambda_a}$

$\lambda_o$ is the observed wavelength

$\lambda_o=\dfrac{v\lambda_a}{c}+\lambda_a\\\\\lambda_o=\dfrac{6.65\times 10^6\times 5.13\times 10^{-7}}{3\times 10^8}+5.13\times 10^{-7}\\\\\lambda_o=5.24\times 10^{-7}\ m$

So, the observed wavelength on Earth from that hydrogen atom is $5.24\times 10^{-7}\ m$ . Hence, this is the required solution.

8 0

3 years ago