I always thought he was in it
Answer:
Option A - the moment of inertia of the system decreases and the angular speed increases.
Explanation:
The moment of Inertia of merry- go-round spins is
I = + mr²
ζ = I
ζ =( + mr²)
= ζ / ( + mr²)
where is the angular speed
increases when the moment of inertia decreases
Therefore, it is true to say that the moment of inertia of the system decreases and the angular speed increases.
Answer;
-The white light shines forward and to both sides (225 Degrees) and is required on all power-driven vessels. A masthead light must be displayed by all vessels when under engine power. The absence of this light indicates a sailboat under sail.
Explanation;
-Masthead light; Means a white light placed over the fore and aft center-line of the vessel showing an unbroken light over an arc of the horizon of 225 degrees and so fixed to show the light from right ahead to 22.5 degrees abaft of the beam on either side of the vessel, except that on a vessel of less than 12 meters (39'4") in length the masthead light shall be placed as nearly as practical to the fore and aft center-line of the vessel.
The momentum of a moving object is given by:
where m is the mass of the object and v its speed.
In this problem, the ball has a mass of
and its momentum is
, so we can rearrange the previous equation to find the speed of the ball:
<u>Answers:
</u>
According to the principle of energy conservation, <u>the energy is not created, nor destroyed, it is transformed.
</u>
Here, we are talking about Mechanical Energy () which is the addition of the Kinetic Energy (energy of the body in motion) and Potential Energy (It can be Gravitational Potential Energy or Elastic Potential Energy, in this case is the first one):
(1)
The units in which the mechanical energy is expressed is Newton*meter ()
So, for this problem we are asked to <u>find only the Potential Gravitational Energy of the eagle</u>. This is mathematically expressed as:
<h2>
(2)
</h2>
Where:
is the mass of the eagle
is the gravity acceleration
is the height at which the eagle is flying
Now, to solve this problem we have to substitute the values in equation (2):
Note that
So, the Potential Gravitational Energy of the Eagle is: