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Amanda [17]
3 years ago
15

What condition must be met for a battery to be rechargeable?

Chemistry
1 answer:
Neko [114]3 years ago
3 0

Answer:

D. The electrochemical reaction of the battery must be reversible.

Explanation:

The batteries are based on the production of an electric flux given by a<u> redox reaction</u>. This reaction is <u>spontaneous</u> and is<u> thermodynamically favored</u>.

Thus, when the reactants to the reaction are finished, the flow of current stops and ends. Therefore, when current is administered from another source, the reaction <u>changes its direction</u> and reagents that were previously consumed begin to occur. Therefore the condition for it to be <u>rechargeable</u> is that the reaction can go <u>forward or backward</u>, that is, it is <u>reversible</u>.

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Consider the following reaction at constant P. Use the information here to determine the value of ΔSsurr at 355 K. Predict whet
Sloan [31]

The given reaction is as follows:

2NO (g) + O₂ (g) = 2NO₂ (g), ΔH = -114 kJ

It is known that dSsurr = -dHsys / T (Temp = 355 K)

So,  dSsurr = - (-114 × 1000) / 355

dSsurr = +321.12 J/K

Hence, the value of dSsurr is +321.12 J/K

For a reaction to be spontaneous, dG<0,

Also dStotal = dSsys + dSsurr > 0

It is known that dG = dHsys - TdSsys,

Now let us assume,

dG<0

Also, dStotal = dSsys + dSsurr > 0

(-114 × 1000) - (355 × dSsys) <0

355 × dSsys > -114 × 1000

dSsys > -321

dSsys >dSsurr

dSsys + dSsurr > 0

dStotal > 0

Thus, the assumption is correct, and the given reaction is spontaneous. Hence, the final answer is Ssurr = +321 J/K reaction is spontaneous.



8 0
3 years ago
Amy performed an experiment in lab. She improperly mixed the chemicals, and an explosion of light, sound, and heat occurred. Whe
agasfer [191]

The answer is D transformed

4 0
4 years ago
Which will most likely result if the levels of dissolved oxygen decrease in a body of water?
Lerok [7]

Answer:

B) Native fish species will begin to decrease in population size.

Hope it helps:D

5 0
3 years ago
Read 2 more answers
Calculate the concentration (in m) of hydroxide ions in a solution at 25. 0 °C with a poh of 3. 58.
Reika [66]

The concentration (in M) of hydroxide ions in a solution at 25°C with a pOH of 3.58 is 2.6 × 10⁻⁴ M.

pOH is the measure of basic nature of a solution by evaluating the [OH⁻] concentration.

It is the negative logarithm of the hydroxide ion concentration.

Given,

pOH = 3.58

Temperature = 25°C = 298K

At 25°C, the relation of pOH and [OH⁻] concentration is as follows:

∴ pOH = -log [OH⁻]

⇒ 3.58 = -log [OH⁻]

⇒log [OH⁻] = -3.58

⇒ [OH⁻] = antilog (-3.58)

⇒[OH⁻] = 2.6 × 10⁻⁴ M

The concentration (in m) of hydroxide ions in a solution at 25.0 °C with a pOH of 3. 58 is 2.6 × 10⁻⁴ M.

Learn more about pOH here, brainly.com/question/17144456

#SPJ4

3 0
2 years ago
Does electronegativity affect replacement reactions
Annette [7]

Answer: A single replacement reaction occurs when an elemental metal atom with a low electronegativity replaces another atom (usually a metal) in a compound. This is caused by a transfer of electrons from the less electronegative metal to the more electronegative atom.

Explanation: I hope this helps

3 0
3 years ago
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