The molar solubility of zns is 1.6 Ã 10-12 m in pure water. Calculate the ksp for zns.

Chemistry

1 answer:

Oksi-84 [34.3K]3 years ago

5 0

Answer:

The solubility product of zinc sulfide is $2.56\times 10^{-24}$ .

Explanation:

Solubility of the zinc sulfide = $S=1.6\times 10^{-12}$

$ZnS\rightleftharpoons Zn^{2+}+S^{2-}$

S S

The expression of solubility product is given by :

$K_{sp}=[Zn^{2+}]\times [S^{2-}]$

$K_{sp}=S\times S=S^2$

$=1.6\times 10^{-12}\times 1.6\times 10^{-12}=2.56\times 10^{-24}$

The solubility product of zinc sulfide is $2.56\times 10^{-24}$ .

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The decomposition of NH4HS is endothermic: NH4HS(s)⇌NH3(g)+H2S(g) Part A Which change to an equilibrium mixture of this reaction

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Explanation:

According to Le Chatelier's principle, any disturbance caused in an equilibrium reaction will shift the equilibrium in a direction that will oppose the change.

As the given reaction is as follows.

$NH_{4}HS(s) \rightleftharpoons NH_{3}(g) + H_{2}S(g)$

(a) When increase the temperature of the reactants or system then equilibrium will shift in forward direction where there is less temperature. It is possible for an endothermic reaction.

Thus, formation of $H_{2}S$ will increase.

(b) When we decrease the volume (at constant temperature) of given reaction mixture then it implies that there will be increase in pressure of the system. So, equilibrium will shift in a direction where there will be decrease in composition of gaseous phase. That is, in the backward direction reaction will shift.

Hence, formation of $H_{2}S$ will decrease with decrease in volume.