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Katen [24]
3 years ago
14

2NaBr + Cl2 → 2 ------ + ------- 2

Chemistry
2 answers:
grigory [225]3 years ago
4 0

Answer:

<h2><em><u>2NaCl2</u></em><em><u>+</u></em><em><u>Br</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em></h2>

<em><u>hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>helps</u></em><em><u> </u></em><em><u>u</u></em><em><u> </u></em>

blondinia [14]3 years ago
3 0

Answer:

its 2nacl +br2.

hope it will help uh..

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Answer:

B ) Known as the Age of Mammals

Explanation:

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5 0
3 years ago
Read 2 more answers
Consider the conversion of a substance from solid to liquid. At one atmosphere pressure and at the normal melting point of the s
Rudik [331]

answer Delt G = 0 for the equilibrium

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4 years ago
Answer the following questions in one word.
Elis [28]

Answer:

its a feeling accompanied by different situation.

Explanation:

For instance; when we are having a lot of problems,obstacles, hindrances at the path of success we feel pain. Secondly,When we are left by someone then we feel sad.last but not the least while we are getting a lot of love from someone whom we love a lot, at this moment we can feel a state of happiness.

4 0
4 years ago
Pentacarbonyliron(0) (fe(co)5) reacts with phosphorous trifluoride (pf3) and hydrogen, releasing carbon monoxide: fe(co)5+2pf3+h
vladimir1956 [14]

The limiting reactant can be determined by calculating the moles supplied / moles stoich ratio and the lowest is the limiting reactant.

Fe(CO)5 ratio = [6 g / 195.9 g/mol] / 1

Fe(CO)5 ratio = 0.0306

 

PF3 ratio = [4 g / 87.97 g/mol] / 2

PF3 ratio = 0.0227

 

H2 ratio = [4 g / 2 g/mol] / 1

H2 ratio = 2

 

<span>We can see that PF3 has the lowest ratio, so it is the limiting reactant.</span>

6 0
4 years ago
Write the equilibrium constant for this reaction in terms of the equilibrium constants, Ka and Kb, for reactions a and b below:
Mars2501 [29]

Answer:

(a) Ka = \frac{(SO3)^{2} }{(S)^{2}*(O2)^{3}  }

(b) Kb = \frac{(SO2)^{1} }{(S)^{1} *(O2)^{1} }

Explanation:

Correct equation: 2S(s) + 3O_{2}(g) ⇒ 2SO_{3}(g)\\

S(s) + O_{2}(g) ⇒ 2SO_{2}(g)\\

Equilibrium constant refers to a relation between products and reactants of an equilibrium reaction with respect to the components concentration and coefficients.

generally in an equilibrium reaction between reactant A, B, C and D shown below

aA+bB ⇒ cC + dD

the equilibrium constant is represented by

k = \frac{C^{c} *D^{d} }{A^{a} *B^{b} }

comparing this with the equation in the problem the equilibrium constants ka and kb are;

Ka = \frac{(SO3)^{2} }{(S)^{2}*(O2)^{3}  }

Kb = \frac{(SO2)^{1} }{(S)^{1} *(O2)^{1} }

7 0
3 years ago
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