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Kobotan [32]
3 years ago
8

A molecule contains 23.24 g iodine (I),

Chemistry
1 answer:
gavmur [86]3 years ago
7 0
Convert each amount of grams into moles:

I: 23.24g x 1 mol / 126.90g = 0.1831 mol I

C: 2.198 x 1 mol / 12.01g = 0.1830 mol C

N: 2.562 x 1 mol / 14.01g = 0.1829 mol N

Each element has roughly the same amount of moles, which means the whole number ratio between the elements is 1:1:1

Therefore the empirical formula is ICN
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What is the pH of a 5.09 x 10-5 M solution of NaOH?
Varvara68 [4.7K]

<u>Answer:</u> The pH of the solution is 9.71

<u>Explanation:</u>

1 mole of NaOH produces 1 mole of sodium ions and 1 mole of hydroxide ions.

We are given:

pOH of the solution = 7.2

To calculate the pH of the solution, we need to determine pOH of the solution. To calculate pOh of the solution, we use the equation:

pOH=-\log[OH^-]

We are given:

[OH^-]=5.09\times 10^{-5}M

Putting values in above equation, we get:

pOH=-\log(5.09\times 10^{-5})\\\\pOH=4.29

To calculate pH of the solution, we use the equation:

pH+pOH=14\\pH=14-4.29=9.71

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7 0
3 years ago
The pH of a substance can only be determined when it is
NeTakaya
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3 years ago
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A student performed a chemical reaction in which 35 grams of hydrogen and 65 grams of oxygen reacted to form water. What is the
sergejj [24]

Answer:

The mass of the product is 73,06 g

Explanation:

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2 moles of H2 __reacts with __ 1 mol O2

17,5 moles of H2 __ reacts with ___ (17,5 m . 1 m) / 2 m = 8,75 m

I have just 2,03 m of O2 and I need 8,75 m so O2 is my limiting reagent

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<u><em>"All operations are done with the limiting reagent"</em></u>

1 mol O2 are required____ to form 2 H2O

2,03 mol O2 are required __ to form (2,03m . 2m) / 1m = 4,06 m

Molar mass of water: 18 g/m

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