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Harrizon [31]
3 years ago
10

How many atoms are in 1.14 mol so3?

Chemistry
2 answers:
jekas [21]3 years ago
6 0
NA = 6.022*10^23
number of atoms = number of moles * avogadros number
number of atoms = <span>6.022*10^23 * 1.14 moles * 4 atoms / molecules of SO3
</span>Number of atoms = 2.75×<span>10^24</span><span> atoms.</span>
Lady bird [3.3K]3 years ago
3 0
1 mol ------------- 6.02x10²³ atoms
1.14 moles ------ ( atoms )

atoms = 1.14 x ( 6.02x10²³) / 1

atoms = 6.86 x 10²³ / 1

= <span> 6.86 x 10²³ atoms

hope this helps!</span>
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Be sure to answer all parts.
tangare [24]

Answer:

(a) cesium bromide (CsBr): 9.15 grams

(b) calcium sulfate (CaSO4):  5.85 grams

(c) sodium phosphate (Na3PO4): 7.05 grams

(d) lithium dichromate (Li2Cr2O7):  9.88 grams

(e) potassium oxalate (K2C2O4):   7.15 grams

Explanation:

<u>(a) cesium bromide (CsBr):</u>

Molar mass of CsBR = 212.81 g/mol

Number of moles = molarity * volume

Number of moles = 0.100 M *0.43 L

Number of moles = 0.043 moles

Mass of CsBr required = moles * Molar mass

Mass of CsBr required = 0.043 moles * 212.81 g/mol

Mass of CsBr required = 9.15 grams

<u>(b) calcium sulfate (CaSO4):</u>

Molar mass of CaSO4 = 136.14 g/mol

Mass of CaSO4 required = moles * Molar mass

Mass of CaSO4 required = 0.043 moles * 136.14 g/mol

Mass of CaSO4 required = 5.85 grams

<u>(c) sodium phosphate (Na3PO4):</u>

Molar mass of Na3PO4 = 163.94 g/mol

Mass of Na3PO4 required = moles * Molar mass

Mass of Na3PO4 required = 0.043 moles * 163.94 g/mol

Mass of Na3PO4 required = 7.05 grams

<u>(d) lithium dichromate (Li2Cr2O7):</u>

Molar mass of Li2Cr2O7 = 229.87 g/mol

Mass of Li2Cr2O7 required = moles * Molar mass

Mass of Li2Cr2O7 required = 0.043 moles * 229.87 g/mol

Mass of Li2Cr2O7 required = 9.88 grams

<u>(e) potassium oxalate (K2C2O4):</u>

Molar mass of K2C2O4 = 166.22 g/mol

Mass of K2C2O4 required = moles * Molar mass

Mass of K2C2O4 required = 0.043 moles * 166.22 g/mol

Mass of K2C2O4 required = 7.15 grams

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Explanation:

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