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jarptica [38.1K]
2 years ago
8

The work-energy theorem states that the work done on an object is equal to a change in which quantity?

Physics
1 answer:
Fynjy0 [20]2 years ago
8 0

The work-energy theorem states that the net work done by the forces on an object equals the change in its kinetic energy.

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A 215-kg merry-go-round in the shape of a uniform, solid, horizontal disk of radius 1.50 m is set in motion by wrapping a rope a
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Answer:

303.9481875 N

Explanation:

t = Time taken = 2 seconds

F = Force

r = Radius = 1.5 m

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Torque

\tau=F\times r

\tau=I\times \alpha

\\\Rightarrow F\times r=I\times \alpha\\\Rightarrow F=\frac{I\times \alpha}{r}

Angular velocity

\omega=rev/s\times 2\pi\\\Rightarrow \omega=0.6\times 2\pi\\\Rightarrow \omega=3.76991\ rad/s

Angular acceleration

\alpha=\frac{\omega}{t}\\\Rightarrow \alpha=\frac{3.76991}{2}\\\Rightarrow \alpha=1.88495\ rad/s^2

I=\frac{1}{2}mr^2\\\Rightarrow I=\frac{1}{2}215\times 1.5^2\\\Rightarrow I=241.875\ kgm^2

F=\frac{I\times \alpha}{r}\\\Rightarrow F=\frac{241.875\times 1.88495}{1.5}\\\Rightarrow F=303.9481875\ N

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3 0
3 years ago
In a microwave oven, electrons describe circular motion in a magnetic field within a special tube called amagnetron; as you'll l
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Answer:

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Diameter = 2.62 mm

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Using formula of the magnetic field strength

B=\dfrac{2\pi mf}{e}

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B=\dfrac{2\times3.14\times9.1\times10^{-31}\times2.15\times10^{9}}{1.6\times10^{-19}}

B=0.077\ T

(B). We need to calculate the energy of electron

Using formula of energy

E=\dfrac{1}{2}m(r\omega)^2

E=\dfrac{1}{2}\times9.1\times10^{-31}\times(1.31\times10^{-3}\times2\pi\times2.15\times10^{9})^2

E=1.4249\times10^{-16}\ J

The energy in eV

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E=\dfrac{1.4249\times10^{-16}}{1.6\times10^{-16}}

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Hence, The magnetic field strength and the electrons' energy are 0.077 T and 0.8906 eV.

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