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Nataly_w [17]
3 years ago
5

How does the electric force between two charged particles change if one particle's charge is increased by a factor of 2?

Physics
2 answers:
Burka [1]3 years ago
8 0
 if one of the charge is doubled, the electric potential energy would be doubled too
Ray Of Light [21]3 years ago
5 0

C. It is increased by a factor of 2.   :) APEX

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An infant's toy has a 120 g wooden animal hanging from a spring. If pulled down gently, the animal oscillates up and down with a
Morgarella [4.7K]

Answer:

0.37 m

Explanation:

The angular frequency, ω, of a loaded spring is related to the period, T,  by

\omega = \dfrac{2\pi}{T}

The maximum velocity of the oscillation occurs at the equilibrium point and is given by

v = \omega A

A is the amplitude or maximum displacement from the equilibrium.

v = \dfrac{2\pi A}{T}

From the the question, T = 0.58 and A = 25 cm = 0.25 m. Taking π as 3.142,

v = \dfrac{2\times3.142\times0.25\text{ m}}{0.58\text{ s}} = 2.71 \text{ m/s}

To determine the height we reached, we consider the beginning of the vertical motion as the equilibrium point with velocity, v. Since it is against gravity, acceleration of gravity is negative. At maximum height, the final velocity is 0 m/s. We use the equation

v_f^2 = v_i^2+2ah

v_f is the final velocity, v_i is the initial velocity (same as v above), a is acceleration of gravity and h is the height.

h = \dfrac{v_f^2 - v_i^2}{2a}

h = \dfrac{0^2 - 2.71^2}{2\times-9.81} = 0.37 \text{ m}

3 0
3 years ago
Que fuerza será necesaria aplicar a un cuerpo de 20kg de masa para imprimirle una aceleración a=4m/s²
WARRIOR [948]

Answer:

La fuerza que será necesaria aplicar a un cuerpo de 20kg de masa para imprimirle una aceleración a=4m/s² es 80 N.

Explanation:

La segunda ley de Newton, llamada ley fundamental o principio fundamental de la dinámica, plantea que un cuerpo se acelera si se le aplica una fuerza.

De esta manera, esta ley establece que las aceleraciones que experimenta un cuerpo son proporcionales a las fuerzas que recibe. Dicho de otra forma, la aceleración de un cuerpo es proporcional a la fuerza neta que se le aplica. Cuanto mayor es la fuerza que se le aplica a  un objeto con una masa dada, mayor será su aceleración.

La segunda Ley de Newton se expresa matemáticamente como:

F = m*a

Donde:

  • F es la fuerza neta. Se expresa en Newton (N)
  • m es la masa del cuerpo. Se expresa en kilogramos (Kg.).
  • a es la aceleración que adquiere el cuerpo. Se expresa en metros sobre segundo al cuadrado (m/s²).

En este caso:

  • m= 20 kg
  • a= 4 m/s²

Reemplazando:

F= 20 kg* 4 m/s²

Resolviendo:

F= 80 N

<u><em>La fuerza que será necesaria aplicar a un cuerpo de 20kg de masa para imprimirle una aceleración a=4m/s² es 80 N.</em></u>

4 0
3 years ago
URGENT PLEASE HELP!!!!
AlexFokin [52]
It just completely stops kinetic energy is movement so technically it would stop.
6 0
3 years ago
A 1.5 kg ballistic cart, moving at 2.8 m/s, ejects a 25 g ball vertically with an initial velocity of 6.5 m/s. What is the magni
Novay_Z [31]

The magnitude of the initial velocity of the ball relative to the ground is 9.3 m/s.

<h3>What is relative velocity?</h3>

Relative velocity is the velocity of an object relative to another moving in the same plane. On frame of reference is used when measuring relative velocity.

The velocity of the ball relative to the ground  is the sum of the velocity of the ballistic cart and the velocity in which the ball is ejected.

The velocity of the ball relative to the ground = 6.5 m/s + 2.8 m/s = 9.3 m/s

In conclusion, relative velocity measures the velocity of an object from a reference point.

Learn more about relative velocity at: brainly.com/question/24337516

#SPJ1

7 0
2 years ago
A ball is thrown vertically upward with an initial velocity of 23.6 meters per second. What is the maximum height reached by the
REY [17]

Answer:

Maximum height attained by the ball will be h = 28.416 m

Explanation:

We have given initial speed of the ball u = 23.6 m /sec

At maximum height velocity will be zero so final velocity v = 0 m/sec

Acceleration due to gravity g=9.8m/sec^2

From law of motion we know that v^2=u^2-2gh

0^2=23.6^2-2\times 9.8\times h

h = 28.416 m

So maximum height attained by the ball will be h = 28.416 m

8 0
3 years ago
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