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3 years ago

What is the function of deaerator in thermal power plant?

Engineering

1 answer:

avanturin [10]3 years ago

3 0

Answer:

The function of the Deaerator is to remove dissolved non-condensable gases and to heat boiler feed water.

Explanation:

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3 years ago

Which of the following materials will prevent the flow of electricity?

RUDIKE [14]

Electricity is not good at conducting through rubber materials so rubber tires would be the correct answer

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3 years ago

Read 2 more answers

A specimen of copper having a rectangular cross section 15.2 mm × 19.1 mm (0.60 in. × 0.75 in.) is pulled in tension with 44,500

lukranit [14]

Answer:

The resulting strain is $1.39\times 10^{-3}$ .

Explanation:

A specimen of copper having a rectangular cross section 15.2 mm × 19.1 mm

Force, F = 44,500 N

Th elastic modulus of Cu to be 110 GPa

The resulting strain is given by the formula as follows :

$\epsilon=\dfrac{F}{AE}$

E is elastic modulus of Cu is are of cross section

$\epsilon=\dfrac{44500}{15.2\times 19.1\times 10^{-6}\times 110\times 10^9}\\\\\epsilon=1.39\times 10^{-3}$

So, the resulting strain is $1.39\times 10^{-3}$ .

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4 years ago

You plan to install an active, liquid-based solar heating system for hot water. There are four candidate collector systems. Your

olchik [2.2K]

Solution:

The given formula,

$x=F_{R} U_{L} \times \frac{P l}{F R_{1}} \times\left(T_{r e f}-\bar{T}_{a}\right) \Delta t \times \frac{A_{c}}{L}$

$y=F_{R}(\tau \alpha)_{n} x \frac{F_{R}^{\prime}}{F_{R}} \times \frac{(\bar{\tau} d)}{(T d)_{n}} \times \bar{H}_{T} N \times \frac{A C}{L}$

$\frac{x}{y}=\frac{ u_{L} \times\left(T_{x t}-\bar{T}_{a}\right) \times \Delta t}{\left(\tau_{x}\right)_{h} \times\left(\frac{\bar{\tau}_{d}}{\left.| \tau_{d}\right)_{n}}\right) \times \bar{H}+N}$

From the table,

$1) $\quad x=2 \cdot 87, \quad y=0.96$\\$\frac{x}{y}=\frac{2187}{0.96}$22895\\\\2) $x=3 \cdot 466 \cdot y=6 \cdot 998$\\$\frac{x}{y}=\frac{3 \cdot 466}{0.898}$$=3 \cdot 4729$$

$3$x=3 \cdot 229, y=1 \cdot 08$\\$\frac{x}{x}=\frac{3 \cdot 229}{1 \cdot 08}$\\=2.9898\)\\\\4) $x=6.525, y=1.094$\\$\frac{x}{y}=\frac{5.625}{1.094}$\\=5.0502$

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4 years ago

Given: There is a rectangular weir that causes the water level in a trapezoidal concrete-lined channel to be 13.1 ft from the ch

Sav [38]

Answer:

The channel distance affected by the weir

Yn ( Normal depth ) = 5.71 ft

Yc ( critical depth ) = 4.11 ft

x = 22794 ft

Explanation:

Attached below is a detailed solution to the problem

The channel distance affected by the weir

Yn ( Normal depth ) = 5.71 ft

Yc ( critical depth ) = 4.11 ft

x = 22794 ft

4 0

3 years ago

What is the function of deaerator in thermal power plant? ​

What is the function of deaerator in thermal power plant?