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DiKsa [7]
3 years ago
5

What are two statements about a true system

Chemistry
1 answer:
zimovet [89]3 years ago
8 0

Answer:

Let me know what is your questions!!

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Which of the following can be said about the boiling point of a liquid
Elodia [21]

The boiling point (or condensation point) of a substance is defined as the temperature at which the vapor pressure of the liquid is exactly equal to the external pressure. Above the boiling point, the substance exists as a gas and below, it exists predominately as a liquid.

3 0
3 years ago
What is a caliper used for
photoshop1234 [79]
To measure the distance between two opposite sides of an object
8 0
4 years ago
A fish tank holds 45 gal of water. How many kilograms of water are in the fish tank?
larisa [96]

Answer:

How to convert 45 gal to kg? You can use the following formula to convert from Gallon to Kilograms :

X(kg) = y(gal) / 0.264172053

To convert 45 Gallon to Kilograms:

X(oz) = 45(gal) / 0.264172053

Answer: 170.3435 kg

7 0
2 years ago
Calculate the amount of heat that must be absorbed by 10.0 g of ice at –20°C to convert it to liquid water at 60.0°C. Given: spe
Murljashka [212]

Answer:

The amount of heat to absorb is 6,261 J

Explanation:

Calorimetry is in charge of measuring the amount of heat generated or lost in certain physical or chemical processes.

The total energy required is the sum of the energy to heat the ice from -20 ° C to ice of 0 ° C, melting the ice of 0 ° C in 0 ° C water and finally heating the water to 60 ° C.

So:

  • Heat required to raise the temperature of ice from -20 °C to 0 °C

Being the sensible heat of a body the amount of heat received or transferred by a body when it undergoes a temperature variation (Δt) without there being a change of physical state (solid, liquid or gaseous), the expression is used:

Q = c * m * ΔT

Where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation (ΔT=Tfinal - Tinitial).

In this case, m= 10 g, specific heat of the ice= 2.1 \frac{J}{g*C} and ΔT=0 C - (-20 C)= 20 C

Replacing: Q= 10 g*2.1 \frac{J}{g*C} *20 C and solving: Q=420 J

  • Heat required to convert 0 °C ice to 0 °C water

The heat Q necessary to melt a substance depends on its mass m and on the called latent heat of fusion of each substance:

Q= m* ΔHfusion

In this case, being 1 mol of water= 18 grams: Q= 10 g*6.0 \frac{kJ}{mol} *\frac{1 mol of water}{18 g}= 3.333 kJ= 3,333 J (being kJ=1,000 J)

  • Heat required to raise the temperature of water from 0 °C to 60 °C

In this case the expression used in the first step is used, but being: m= 10 g, specific heat of the water= 4.18 \frac{J}{g*C} and ΔT=60 C - (0 C)= 60 C

Replacing: Q= 10 g*4.18 \frac{J}{g*C} *60 C and solving: Q=2,508 J

Finally, Qtotal= 420 J + 3,333 J + 2,508 J

Qtotal= 6,261 J

<u><em> The amount of heat to absorb is 6,261 J</em></u>

<u><em></em></u>

3 0
3 years ago
What is a good title for this chart?
Elina [12.6K]

Answer:

pH of the acid

Explanation:

8 0
3 years ago
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