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3 years ago

What are the 2 types of crystallization ?

Physics

2 answers:

irinina [24]3 years ago

5 0

Answer:

evaporative crystallization

cooling crystallization from solution or the melt

trasher [3.6K]3 years ago

5 0

Answer:

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PLZ HELP IM REALLY CONFUSED a boy is playing catch with his friend. He throws the ball straight up. When it leaves his hand, the

erastovalidia [21]

Answer:

K.E = 100 J

Final P.E = 100 J

Explanation:

The kinetic energy of any object can be given by the following formula:

$K.E = (\frac{1}{2})mv^{2}$

where,

K.E = Kinetic Energy

m = mass of ball = 2 kg

v = speed of ball

Initially, v = 10 m/s. Therefore, the initial K.E is given as:

$K.E = (\frac{1}{2})(2\ kg)(10\ m/s)^{2}$

Now, at the highest point the K.E of the ball becomes zero. because the ball stops for a moment at the highest point and its velocity becomes zero. So, from Law of Conservation of energy:

Initial K.E + Initial P.E = Final K.E + Final P.E

Initial P.E is also zero due to zero height initially.

K.E + 0 = 0 + Final P.E

<u>Final P.E = 100 J</u>

3 0

3 years ago

Suppose a yo-yo has a center shaft that has a 0.230 cm radius and that its string is being pulled.

Fofino [41]

Answer:

Part a)

$\alpha = 782.6 rad/s^2$

Part B)

$\omega = 587 rad/s$

Part c)

$a_t = 24.3 m/s^2$

Explanation:

Part a)

As we know that

$a = R \alpha$

so we will have

$a = 1.80 m/s^2$

$R = 0.230 cm$

$\alpha = \frac{a}{R}$

$\alpha = \frac{1.80}{0.230 \times 10^{-2}}$

$\alpha = 782.6 rad/s^2$

Part B)

Angular speed of the yo-yo

$\omega = \alpha t$

so we have

$\omega = 782.6 \times 0.750$

$\omega = 587 rad/s$

Part c)

Tangential acceleration is given as

$a_t = R \alpha$

$a_t = (3.10 \times 10^{-2})(782.6)$

$a_t = 24.3 m/s^2$

6 0

3 years ago

Cell phones require powerful batteries in order to work effectively. Which

iragen [17]

Answer:

D. Improving their design to make it easier to recycle them when they are no longer useful.

Explanation:

Just took the test on (APEX)!!

7 0

3 years ago

Which equation is correct according to Ohm’s law?

Korvikt [17]

You didn't give us anything other than the question. No options are provided so I cannot answer. Nobody can.

4 0

3 years ago

Read 2 more answers

Which of the following statements about sunspots is false? a. They are areas of the sun that are "burnt out." c. They are cooler

PSYCHO15rus [73]

Answer: Option (a) is the correct answer.

Explanation:

Sunspots are defined as the dark and cooler areas on the surface of the Earth. A sunspot is present in a region known as photosphere.

Temperature of a sunspot is about 3,800 degrees Kelvin whereas photosphere has a temperature of about 5,800 degree kelvin.

Thus, we can conclude that out of the given options, the statement they are areas of the sun that are "burnt out" is false about sunspots.

8 0

3 years ago

Read 2 more answers