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Lapatulllka [165]
3 years ago
7

17. How far did a car travel if it was on the road for 1 hours and 23 minutes and traveled at an aver

Physics
1 answer:
zloy xaker [14]3 years ago
5 0

Answer:

1)    Givens:         time - 1 hr 23 min

     Unknown:     displacement, velocity

     Equation:      d = v x t

      Substitute:     -

      Solve:            -

2)  Givens:          velocity - 67 m/s; distance - 550 m

    Unknown:    time

    Equation:     t = d/v  s

    Substitute:   t = 550/67  s

    Solve:          t = 8.21 s

Explanation:

The relation between the velocity, displacement, and time is given by the equation,

                                           velocity = displacement / time

Or, displacement of a body is equal to the product of its velocity and time taken to travel the distance.

If there are two knowns in the equation, the unknown can be calculated from the above relation.

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When someone yells in it
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3 years ago
You are travelling at 60.0 mph on the Grand Central Parkway near exit 10 where it is (nearly) parallel to the Long Island Expres
Romashka-Z-Leto [24]

Answer:

a)Vr= 5 mph

b)Vr= 115 mph

Explanation:

Lets

your velocity ,u= 60 mph

velocity of truck ,v= 55 mph

When object are moving in opposite direction the relative velocity  = u +v When object are moving in opposite direction the relative velocity  = u - v

a)

Truck is moving in the same direction ,so the  relative velocity

Vr= = u - v

Vr= 60 - 55

Vr= 5 mph

b)

Truck is moving in the opposite direction ,so the  relative velocity

Vr= = u+v

Vr= 60 + 55

Vr= 115 mph

4 0
3 years ago
I need help please. Quick.
Nezavi [6.7K]

Answer:

look on google i had to do the same thing i look in google

Explanation:

8 0
3 years ago
an object has 5.00 kg*m/s of momentum. if you double the mass and double the velocity, how much momentum would it have PLEASE HE
KIM [24]

The final momentum is 20.00 kg*m/s

Explanation:

The momentum of an object is given by:

p=mv

where

m is the mass of the object

v is its velocity

For the object in the problem, the initial momentum is

p=mv=5.00 kg m/s

Then, the mass is doubled:

m' = 2m

And the velocity is also doubled:

v' = 2v

So, the new momentum will be:

p'=m'v'=(2m)(2v)=4(mv) = 4p = 4(5.00)=20 kg m/s

So, the final momentum is 4 times the initial momentum.

Learn more about momentum:

brainly.com/question/7973509

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6 0
4 years ago
Modeled after the two satellites problem (slide 12 in Lecture13, Universal gravity), imagine now if the period of the satellite
ikadub [295]

Answer:

  R = 6.3456 10⁴  mile

Explanation:

For this exercise we will use Newton's second law where force is gravitational force

      F = m a

The satellite is in a circular orbit therefore the acceleration is centripetal

      a = v² / r

Where the distance is taken from the center of the Earth

     G m M / r² = m v² / r

     G M / r = v²

The speed module is constant, let's use the uniform motion relationships, with the length of the circle is

     d = 2π  r

     v = d / t

The time for a full turn is called period (T)

Let's replace

     G M / r = (2π r / T)²

     r³ = G M T²²2 / 4π²

     r = ∛ (G M T² / 4π²)

We have the magnitudes in several types of units

      T = 88.59 h (3600 s / 1h) = 3.189 10⁵ s

      Re = 6.37 10⁶ m

Let's calculate

     r = ∛ (6.67 10⁻¹¹ 5.98 10²⁴ (3,189 10⁵)²/4π²)

     r = ∛ (1.027487 10²⁴)

     r = 1.0847 10⁸ m

This is the distance from the center of the Earth, the distance you want the surface is

     R = r - Re

     R = 108.47 10⁶ - 6.37 10⁶

     R = 102.1 10⁶ m

Let's reduce to miles

      R = 102.1 10⁶ m (1 mile / 1609 m)

     

      R = 6.3456 10⁴  mile

6 0
3 years ago
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