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Mandarinka [93]
3 years ago
11

A mass attached to a vertical spring causes the spring to stretch and the mass to move downwards. What can you say about the pot

ential energy of the spring Usp and gravitational potential energy of the mass, Ug?
Physics
2 answers:
poizon [28]3 years ago
8 0

Complete Question

A mass attached to a vertical spring causes the spring to stretch and the mass to move downwards. What can you say about the spring's potential energy Us and the gravitational potential energy Ug of the mass?

A. both Us and Ug decrease

B. Us increases and Ug decreases

C Both Us and Ug increase

D Us decreases and Ug increases

E Us increases and Ug is constant

Answer:

Option B is the correct Answer

Explanation:

    The Gravitational Potential energy is mathematically represented as  

                    U_g = mgh

Where m is the mass , g is the acceleration due to gravity while and h is the height

 And in term of the spring  this energy represents the workdone against gravitational Force

 The Spring potential energy is mathematically represented as

                     U_s = \frac{1}{2} k x^2

Where k is the spring constant ans  x is the extension in the spring

   And energy represents the work that is being done to stretch the spring

 If the system as state in the question is setup and U_s is being increased then U_g decreases

   

blondinia [14]3 years ago
8 0

Answer:

An increase in Ug causes a decrease in Usp. Also a decrease in Ug causes an increase in Usp of the spring.

Explanation:

For this system, the total mechanical energy of the system is conserved since the only force acting on the system is the force of gravity. As a result the total sum of the potential energies at all times must be equal.

E = Usp1 + Ug1 = Usp2 + Ug2

Now suppose the mass falls through a height h, its potential energy decreases by a magnitude mgh. Because energy is conserved this causes an increase in the potential energy stored in the spring

Ug2 – Ug1 = Usp2 – Usp1 = mgh

Usp2 = -mgh + Usp1

If instead the potential energy of the mass increased this will bring about a reduction in the potential energy of the spring.

In that case

So in essence the mechanical energy of the system always distributes itself in such a way that whatever increases in one accounts for the decrease in another.

So an increase in Ug causes a decrease in Usp. Also a decrease in Ug causes an increase in Usp of the spring.

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1)

In this circuit (see attachment #1), we have:

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- Four resistors: a resistor is a device which opposes to the flow of current. The property that describes by "how much" the resistor "opposes" to the flow of current is called "resistance", and it is indicated with the letter R.

- In this circuit, the 4 resistors are in series. Resistors are said to be in series when they are connected along the same branch of the circuit, so that the same current flow across each of them.

- For resistors in series, the equivalent resistance of the circuit is given by the sum of the individual resistances:

R=R_1+R_2+...+R_n

2)

In this circuit (see attachment #2), we have:

- A voltage source: as before, we have chosen a battery, providing an electromotive  force to the circuit

- Three resistors wired in parallel. Resistors are said to be connected in parallel when they are connected along different branches, but with their terminals connected to the same point, so that each of them has the same potential difference across it.

- For resistors in parallel, the equivalent resistance of the circuit is calculated using the formula:

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3)

In this circuit (see attachment #3), we have:

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-- the 3rd one it is in series with the first two

If we call R_1,R_2 the resistances of the first 2 resistors in parallel, their equivalent resistance is:

\frac{1}{R_{12}}=\frac{1}{R_1}+\frac{1}{R_2}\\\rightarrow R_{12}=\frac{R_1 R_2}{R_1+R_2}

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R=R_{12}+R_3=\frac{R_1R_2}{R_1+R_2}+R_3=\frac{R_1R_2+R_3(R_1+R_2)}{R_1+R_2}

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