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d1i1m1o1n [39]
1 year ago
13

HELPPP PLEASE QUICk :(

Physics
1 answer:
yaroslaw [1]1 year ago
3 0

Evaluate skill performance against a scale is known as Rubrics; option D

<h3>What is performance evaluation?</h3>

Performance evaluation is the systematic process of assessing the performance of an individual in a certain task, skill or job.

Performance evaluation is done against a set of standard measurements or a rating scale known as Rubrics.

Rubrics use a set of specific criteria to evaluate an individual student or a group of students performance in a certain task assigned to them.

Rubrics use  a rating system where points or scores are awarded depending on the skillset level or ability demonstrated.

In conclusion, rubrics are used to evaluate performance.

Learn more about rubrics at: brainly.com/question/3651747

#SPJ1

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Three forces act on a flange as shown below. Determine the magnitude of the unknown force F (in lb) such that the net force acti
Tems11 [23]

Answer:

The unknown force will be 18.116 lb.

Explanation:

Given that,

Three forces act on a flange as shown in figure.

The net force acting on the flange is a minimum.

\dfrac{dF_{net}}{df}=0

We need to calculate the unknown force

Using formula of net force

\vec{F_{net}}=\vec{F_{x}}+\vec{F_{y}}

Put the value into the formula

\vec{F_{net}}=(F\cos45+70\cos30-40)\hat{i}+(70\sin30-F\sin45)\hat{j}

\vec{F_{net}}=(F\cos45+70\times\dfrac{\sqrt{3}}{2})\hat{i}+(70\times\dfrac{1}{2}-F\sin45)\hat{j}

The magnitude of net force,

F_{net}=\sqrt{F_{x}^2+F_{y}^2}

F_{net}=\sqrt{(F\times\dfrac{1}{\sqrt{2}}+60.62)^2+(35-F\times\dfrac{1}{\sqrt{2}})^2}

F_{net}=\sqrt{F^2+(60.62)^2+121.24\times\dfrac{F}{\sqrt{2}}+(35)^2-70\times\dfrac{F}{\sqrt{2}}}

F_{net}=\sqrt{F^2+4899.78+36.232F}

On differentiating w.r.to F

(\dfrac{dF_{net}}{dF})^2=2F+36.232

0=2F+36.232

F=-\dfrac{36.232}{2}

F=-18.116\ lb

Negative sign shows the direction of force which is downward.

Hence, The unknown force will be 18.116 lb.

6 0
2 years ago
Two technicians are discussing a problem where the brake pedal travels too far before the vehicle starts to slow. Technician A s
iVinArrow [24]

Answer:

Technician A

Explanation:

If Technician B was correct, and the master cylinder is defective - then no braking action would occur.

This is not true however, as some breaking action eventually occurs, meaning it must be out of adjustment.

3 0
3 years ago
If I can travel 20m in 18 seconds how far can I go in 10 minutes?
kifflom [539]

Answer:

36 s

Explanation:

20 m = 18 s

10 m = ?

20 × 18 = 360÷ 10

= 36 sec

5 0
2 years ago
What is the approximate weight of a 20-kg cannonball on earth?
disa [49]
The weight of an object is taken to be the force on the object due to gravity. The weight ( W ) is the product of the mass ( m ) of the object and the magnitude of the gravitational acceleration ( g ).
On Earth: g = 9.81 m/s²
m = 20 kg
W = m · g = 20 kg · 9.81 m/s² = 196.2 N
6 0
3 years ago
6) If a mass of an object is decreased to half and acting force is reduced by quarter the acceleration of its motion
Zepler [3.9K]

Answer:

Decreases to half.

Explanation:

From the question given above, the following data were obtained:

Initial mass (m₁) = m

Initial force (F₁) = F

Initial acceleration (a₁) =?

Final mass (m₂) = ½m

Final force (F₂) = ¼F

Final acceleration (a₂) =?

Next, we shall determine a₁. This can be obtained as follow:

F₁ = m₁a₁

F = ma₁

Divide both side by m

a₁ = F / m

Next, we shall determine a₂.

F₂ = m₂a₂

¼F = ½ma₂

2F = 4ma₂

Divide both side by 4m

a₂ = 2F / 4m

a₂ = F / 2m

Finally, we shall determine the ratio of a₂ to a₁. This can be obtained as follow:

a₁ = F / m

a₂ = F / 2m

a₂ : a₁ = a₂ / a₁

a₂ / a₁ = F/2m ÷ F/m

a₂ / a₁ = F/2m × m/F

a₂ / a₁ = ½

Cross multiply

a₂ = ½a₁

From the illustrations made above, the acceleration of the car will decrease to half the original acceleration

7 0
2 years ago
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