Increasing the separation distance between objects decreases the force of attraction or repulsion between the objects. And decreasing the separation distance between objects increases the force of attraction or repulsion between the objects. Electrical forces are extremely sensitive to distance.
Answer:
W= 38.4 J
Explanation:
Given that
m = 80 g= 0.08 kg
Initial speed ,u= 22 m/s
Final speed ,v= 38 m/s
The change in the kinetic energy of the particle
ΔKE= 38.4 J
We know that
Work done by all the forces =Change in the kinetic energy
That is why net work done = 38.4 J.
W= 38.4 J
Therefore the answer will be 38.4 J.
Answer:
x = 7226.94 m
y = 1677.4 m
Explanation:
This is a classic problem of a parabolic move. Let's analyze the given data.
The speed is 300 m/s but it's fired at 55°, so the x and y component of the speed would be:
Vx = 300 cos55 = 172.07 m/s
Vy = 300 sin55 = 245.75 m/s
Now, to get the x and y components of the shell, we need to apply the following expressions:
X = Xo + Vx*t (1)
Y = Yo + Vy*t - 1/2 gt² (2)
Xo and Yo is 0, and we already have the speed in x and y, so the components are:
X = 0 + (172.07)(42)
<h2>
X = 7226.94 m</h2>
For the y component:
Y = 0 + (245.75)(42) - 1/2 (9.8)(42)²
Y = 10321.5 - 8643.6
<h2>
Y = 1677.4 m</h2><h2>
</h2>
Hope this helps
