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3 years ago

How do you move the decimal from megameters to meters?

1 answer:

8 0

The prefix "mega" means million.
Therefore
1 megameter = 10⁶ meters

That is,
1.0 megameter = 1,000,000.0 meters.

Answer:
The decimal is moved right by 6 places to convert a megameter to meters.

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A small grinding wheel has a moment of inertia of 4.0*10-5kgm2. What net torque must be applied to the wheel for its angular acc

kvv77 [185]

Hi there!

We can use the rotational equivalent of Newton's Second Law:

$\huge\boxed{\Sigma \tau = I \alpha}$

Στ = Net Torque (Nm)

I = Moment of inertia (kgm²)

α = Angular acceleration (rad/sec²)

We can plug in the given values to solve.

$\Sigma \tau = (4 * 10^{-5})(150) = \boxed{0.006 Nm}$

4 0

2 years ago

An object has a mass of 50.0 g and a volume of 10.5 cm3. What is the object's density?

vagabundo [1.1K]

The density is 4.76 gcm^-3
and if mass is in kg then density is equal to 4.76*10^-3

3 0

2 years ago

Read 2 more answers

What is the difference between an sa and an sb galaxy? (select all that apply.)

Free_Kalibri [48]

The difference between an sa and sb galaxy is Sa has a larger nucleus and more tightly wound arms than an Sb.

<h3>What is sa Galaxy?</h3>

Sa galaxies are normal spirals that have narrow, tightly wound arms, which usually are visible because of the presence of interstellar dust and, in many cases, bright stars.

<h3>What is sb Galaxy?</h3>

The arms of sb galaxy are more widely spread than those of the Sa variety and appear less smooth.

Thus, the difference between an sa and sb galaxy is Sa has a larger nucleus and more tightly wound arms than an Sb.

Learn more about sa galaxy here: brainly.com/question/9813915

#SPJ11

7 0

2 years ago

Frim the castle wall 20 m high shot an arrow. The initial speed of the bow is 45 m/s directed 40 degrees above horizontal. Find

True [87]

Answer:

Range of arrow = 225.09 meter

Final horizontal velocity = 34.47 m/s

Explanation:

We have equation of motion $s=ut+\frac{1}{2} at^2$ , where u is the initial velocity, t is the time taken, a is the acceleration and s is the displacement.

Considering the vertical motion of arrow ( up direction as positive)

We have u = 45 sin40 = 28.93 m/s, s = -20 m, a = acceleration due to gravity = $-9.8m/s^2$ .

$-20=28.93*t-\frac{1}{2} *9.8*t^2\\ \\ 4.9t^2-28.93t-20=0$

t = 6.53 seconds or t = -0.63 seconds

So time = 6.53 seconds.

Considering the horizontal motion of arrow

u = 45 cos 40 = 34.47 m/s, t = 6.53 s, a = $0m/s^2$

$s=34.47*6.53+\frac{1}{2} *0*6.53^2\\ \\ s=225.09m$

So range of arrow = 225.09 meter

Horizontal velocity will not change , final horizontal velocity = 34.47 m/s.

7 0

3 years ago

According the Merriam Webster dictionary the definition of falling is, "to descend freely by the force of gravity".

ki77a [65]

Answer:

Explained

Explanation:

If you are in a rotating system newton's law do not work .Adding a frictious force can make the law work. If an orbiting object is in constant freefall under gravity . Even elliptical planet orbits are examples of freefall under gravity. The force F which the planet feels; this force can be resolved into two components, centripetal force F_C and tangential force F_T.

The tangential force causes an acceleration(newton's second law) which decreases the speed and the centripetal force causes the velocity to turn. In there is circular orbit of radius R, F_T=0 and the centripetal force is F_C=Mv^2/R;

The centrifugal force would be a vector with magnitude Mv^2/R( same as that of centripetal) pointing away from the sun but it does not really exist.

3 0

3 years ago