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3 years ago

Which subatomic particles are located in the nucleus of a carbon atom?

Chemistry

2 answers:

Papessa [141]3 years ago

5 0

Answer is (3) protons and neutrons.

(P.S. The outer part contains the electrons)

alukav5142 [94]3 years ago

3 0

Not just carbon atoms, but every single other atom has protons and neutrons in their nucleus. (3) is the correct one.
Hope this would help :))

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mina [271]

Answer:

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Explanation:

4 0

3 years ago

________ is the enthalpy change when 1 mole of a substance is formed from its elements under standard conditions.

guajiro [1.7K]

The correct answer is C

6 0

3 years ago

A copper atom has 29 protons and 36 neutrons. What is the mass number of this atom in amu?

Mamont248 [21]

The Mass number is 65, Copper-65

To find the mass number you add the number of protons to the number of neutrons.

4 0

2 years ago

Calculate how many grams of the product form when 16.7 g of oxygen gas completely reacts with solid chromium. Assume that there

34kurt

<u>Answer:</u> The mass of product formed is 79.344 g.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of oxygen = 16.7 g

Molar mass of oxygen = 32 g/mol

Putting values in equation 1, we get:

$\text{Moles of oxygen}=\frac{16.7g}{32g/mol}=0.522mol$

The chemical reaction for the formation of chromium oxide follows the equation:

$4Cr+3O_2\rightarrow 3Cr_2O_3$

By Stoichiometry of the reaction:

3 moles of oxygen produces 3 moles of chromium oxide.

So, 0.522 moles of oxygen will produce = $\frac{3}{3}\times 0.522=0.522mol$ of chromium oxide.

Now, calculating the mass of chromium oxide from equation 1, we get:

Molar mass of chromium oxide = 152 g/mol

Moles of chromium oxide = 0.522 moles

Putting values in equation 1, we get:

$0.522mol=\frac{\text{Mass of chromium oxide}}{152g/mol}\\\\\text{Mass of chromium oxide}=79.344g$

Hence, the mass of chromium oxide produced in the given reaction is 79.344 grams.

3 0

3 years ago

How many moles are in 594 grams of Pb(NO3)4

irga5000 [103]

Molar mass(Pb(NO3)4) =

= 207.2 × 1 + 14 × 4 + 16 × 12 =

= 455.2 g/mol

n(Pb(NO3)4) = 594 g ÷ 455.2 g/mol ~

~ 1.3 mol

6 0

3 years ago