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inessss [21]
3 years ago
13

A student was trying to obtain lithium by electrolysis of aqueous lithium chloride. Was he successful?

Chemistry
1 answer:
Wittaler [7]3 years ago
6 0

The student was not successful.

Consider the standard reduction potentials.

Li⁺ + e⁻ ⇌ Li;                       E° = -3.04 V

2H₂O + 2e⁻ ⇌ H₂ + 2OH⁻; E° = -0.83 V

To reduce Li⁺ to Li, the student must apply 3.04 V.

However, it takes only 0.83 V to reduce water to hydrogen.

Thus, the student will get H₂ instead of Li.

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A piece of metal that has a density of 5.2 g/cm3 and a mass of 100 g was placed in a full jar of water. How many mL of water was
Klio2033 [76]

Answer:

100g / (5.2g/cm3)

= 100g / (5.2g / 1cm3)

= 100g x 1cm3 / 5.2 g

= 19.2 cm3

Since 1 cm3 = 1 ml, your answer is 19.2 ml.

5 0
3 years ago
How many milliliters of 0. 0140 m na2s2o3 solution are needed to dissolve 0. 590 g of agbr? agbr(s) 2na2s2o3(aq)→na3ag(s2o3)2(aq
Marina86 [1]

The molarity of the solution can be used to give the moles and the volume of the solution. The 0.0140 M sodium thiosulfate needs 225 ml of volume.

<h3>What is molarity?</h3>

Molarity is the property of the solution that is given by the ratio of the moles of the solute to the volume of the solution in liters.

Given,

Molarity of Sodium thiosulfate = 0.0140 M

Mass of solute (AgBr) = 0.590 gm

Molar mass of AgBr = 187.77 g/mol

First moles from the mass can be calculated as,

Moles = mass ÷ molar mass

n = 0.590 g ÷ 187.77 g/mol

= 0.00314 moles

Now, the volume of the solution from molarity is calculated as,

Volume = moles ÷ molarity

= 0.00314 moles ÷ 0.0140

= 0.225 L

Therefore, 225 mL is the volume required.

Learn more about molarity here:

brainly.com/question/13889022

#SPJ4

3 0
1 year ago
A 360. g iron rod is placed into 750.0 g of water at 22.5°C. The water temperature rises to 46.7°C. What was the initial tempera
Grace [21]

Answer: The initial temperature of the iron was 515^0C

Explanation:

heat_{absorbed}=heat_{released}

As we know that,  

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]         .................(1)

where,

q = heat absorbed or released

m_1 = mass of iron = 360 g

m_2 = mass of water = 750 g

T_{final} = final temperature = 46.7^0C

T_1 = temperature of iron = ?

T_2 = temperature of water = 22.5^oC

c_1 = specific heat of iron = 0.450J/g^0C

c_2 = specific heat of water= 4.184J/g^0C

Now put all the given values in equation (1), we get

-360\times 0.450\times (46.7-x)=[750\times 4.184\times (46.7-22.5)]

T_i=515^0C

Therefore, the initial temperature of the iron was 515^0C

4 0
3 years ago
The heart has structures called___. This allows the blood to move in one direction.
IrinaVladis [17]
The anwser is valves
7 0
2 years ago
Read 2 more answers
In a laboratory, Carlos places one plate with grape jelly and another plate with cooked brown rice inside an ant farm. The next
olga2289 [7]

Answer:

number 1, 3, and 4 :)

Explanation:

hope you do good in edge!!

4 0
3 years ago
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