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4 years ago

The asthenosphere is a layer whose distinctiveness from the rest of the mantle is based on its ___________.

Physics

2 answers:

gavmur [86]4 years ago

8 0

<span>reduced rigidity should be the answer

</span>

xz_007 [3.2K]4 years ago

7 0

Answer: Viscous property

Explanation: The asthenosphere is the layer that lies below the crust. This layer is generally viscous, where the rocks floats due to deformation. It is the top part of the mantle and generation of convection current pushes the materials to move, thereby breaking the crust, causing it to move in convergent or divergent direction or slide past each other. The composition is same for both the lithosphere and the asthenosphere but it has its viscous property.

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How far from a converging lens with a focal length of 16 cm should an object be placed to produce a real image which is the same

Feliz [49]

Answer:

32 cm

Explanation:

f = focal length of the converging lens = 16 cm

Since the lens produce the image with same size as object, magnification is given as

m = magnification = - 1

p = distance of the object from the lens

q = distance of the image from the lens

magnification is given as

m = - q/p

- 1 = - q/p

q = p eq-1

Using the lens equation, we get

1/p + 1/q = 1/f

using eq-1

1/p + 1/p = 1/16

p = 32 cm

4 0

4 years ago

A sphere is charged with electrons to -6 x 10^-6C. How many electrons make up this charge? The elemental charge is 1.6 x 10^-19

just olya [345]

Answer:

$3.75*10^{-13}$ electrons

Explanation:

The total charge Q is the sum of the charge of the N electrons contained in the sphere:

$Q=N*q_{e}$

$q_{e}=-1.6*10^{-19}C$ charge of a electron

We solve to find N:

$N=\frac{Q}{q_{e}}=\frac{-6 x 10^{-6}}{-1.6 x 10^{-19}}=3.75*10^{-13}$

7 0

4 years ago

A block weighing 400 kg rests on a horizontal surface and supports on top of it ,another block of weight 100 kg which is attache

Paladinen [302]

Answer:

$F_a=1470\ N$

Explanation:

<u>Friction Force</u>

When objects are in contact with other objects or rough surfaces, the friction forces appear when we try to move them with respect to each other. The friction forces always have a direction opposite to the intended motion, i.e. if the object is pushed to the right, the friction force is exerted to the left.

There are two blocks, one of 400 kg on a horizontal surface and other of 100 kg on top of it tied to a vertical wall by a string. If we try to push the first block, it will not move freely, because two friction forces appear: one exerted by the surface and the other exerted by the contact between both blocks. Let's call them Fr1 and Fr2 respectively. The block 2 is attached to the wall by a string, so it won't simply move with the block 1.

Please find the free body diagrams in the figure provided below.

The equilibrium condition for the mass 1 is

$\displaystyle F_a-F_{r1}-F_{r2}=m.a=0$

The mass m1 is being pushed by the force Fa so that slipping with the mass m2 barely occurs, thus the system is not moving, and a=0. Solving for Fa

$\displaystyle F_a=F_{r1}+F_{r2}.....[1]$

The mass 2 is tried to be pushed to the right by the friction force Fr2 between them, but the string keeps it fixed in position with the tension T. The equation in the horizontal axis is

$\displaystyle F_{r2}-T=0$