1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Effectus [21]
3 years ago
15

A car is traveling at 33.2 m/s. If the car has a kinetic energy of 688,900 J, what is the car's mass?​

Physics
2 answers:
wariber [46]3 years ago
7 0

Answer:1250kg

Explanation:

Kinetic energy(ke)=688900j

Velocity(v)=33.2m/s

Mass(m)=?

ke=(mv^2)/2

688900=(mx(33.2)^2)/2

688900x2=mx1102.24

1377800=mx1102.24

m=1377800/1102.24

m=1250kg

aivan3 [116]3 years ago
5 0

Answer:

1250kg

Explanation:

\frac{688900}{33.2\\^{2} } = 625

\frac{1}{2} m = 625

625 x 2 = 1250

You might be interested in
According to the picture, what is the truck doing?
Slav-nsk [51]

Answer:

but were is the picture

how can we see

4 0
3 years ago
Now open the simulation. Activate ""grid"" and ""show numbers"" to read values. Place a 1 nC positive (red color) charge on the
zmey [24]

Answer:

The divergence on the sensor shows the magnitude of the charges

Explanation:

This will increase as length increases since it is said to be proportional to the length. note that test charge is always positive and charge on the grid is positive as indicated (1 nC)

8 0
3 years ago
Can someone please help me with these physics problems? I just don’t even know where to start.
KIM [24]

#1

for the block of mass 5 kg normal force is given as

F_n = mg

F_n = 5*9.8 = 49 N

friction force is given as

F_f = \mu F_n

F_f = 0.1*49 = 4.9 N

Net force is given as

F_{net} = ma

F_{net} = 5*2 = 10 N

now we know that

F_{net} = F_{app} - F_f

10 = F_{app} - 4.9

F_{app} = 14.9 N

#2

Normal force is given as

F_n = mg

F_n = 6*9.8

F_n = 58.8 N

now we know that

F_{net} = F_{app} - F_f

F_{net} = 0

as object moves with constant velocity

F_{app} = F_f = 15 N

now for coefficient of friction we can use

F_f = \mu F_n

15 = \mu * 58.8

\mu = 0.255

#3

net force upwards is given as

F = 1.2 * 10^{-4} N

mass is given as

m = 7 * 10^{-5} kg

now as per newton's law we can say

F = ma

1.2 * 10^{-4} = 7 * 10^{-5} * a

a = 1.71 m/s^2

#4

As we know that when block is sliding on rough surface

part a)

net force = applied force - frictional force

F_{net} = F_{app} - F_f

ma = F_{app} - F_f

5*6 = 40 - F_{f}

F_f = 40 - 30 = 10 N

part b)

for coefficient of friction we can use

F_f = \mu F_n

10 = \mu * F_n

here normal force is given as

F_n = mg = 5*9.8 = 49 N

now we have

\mu = \frac{10}{49} = 0.204

#5

if an object is initially at rest and moves 20 m in 5 s

so we can use kinematics to find out the acceleration

d = v_i*t + \frac{1}{2}at^2

20 = 0 + \frac{1}{2}a(5^2)

a = 1.6 m/s^2

now net force is given as

F_{net} = ma

F_{net} = 10*1.6 = 16 N

#6

an object travelling with speed 25 m/s comes to stop in 1.5 s

so here acceleration of object is given as

a = \frac{v_f - v_i}{t}

a = \frac{0 - 25}{1.5} = -16.67 m/s^2

now the force is gievn as

F = ma

F = 5*16.67 = 83.3 N

3 0
4 years ago
A flea jumps by exerting a force of 1.09 ✕ 10−5 N straight down on the ground. A breeze blowing on the flea parallel to the grou
patriot [66]

Answer:

a= 17.877 m/s² : Magnitude of the acceleration of the flea

β = 88.21°  :  Direction  of the acceleration of the flea

Explanation:

Conceptual analysis

We apply Newton's second law:

∑F = m*a (Formula 1)

∑F : algebraic sum of the forces in Newton (N)

m : mass in kilograms (kg)

a : acceleration in meters over second square (m/s²)

Problem development

Look at the flea free body diagram in the attached graphic

The acceleration is presented in the direction of the resultant force (R) applied over the flea .

R= \sqrt{(F_{x})^{2} + (F_{y})^{2} }

R= \sqrt{(10.9)^{2}+(0.340)^{2}  } *10^{-6} N

R= 10.905*10⁻⁶ N

We apply the formula (1) to calculate the magnitude of the acceleration of the flea

∑F = m*a   m = 6.1 * 10⁻⁷ kg

R = m*a

a= R/m

a= (10.905*10⁻⁶) /  (6.1 * 10⁻⁷ )

a= 17.877 m/s²

β: Direction and magnitude of the acceleration of the flea

\beta = tan^{-1} (\frac{F_{y} }{F_{x} } )

\beta = tan^{-1} (\frac{10.9*10^{-6} }{0.340*10^{-6} } )

β = 88.21°

5 0
4 years ago
A rod of 2.0-m length and a square (2.0 mm X 2.0 mm) cross section is made of a material with a resistivity of 6.0 E–8 Ohm meter
Alex Ar [27]

Answer:

8.33*10^-16 Watt

Explanation:

Given that

Length of the rod, l = 2 m,

Area of the rod, A = 2 x 2 mm² = 4*10^-6 m²

resistivity of the rod, p = 6*10^-8 ohm metre,

Potential difference of the rod, V = 0.5 V

Let R be the resistance of the rod, then

R = p * l / A

R = (6*10^-8 * 2) / (4*10^-6)

R = 3*10^14 ohm

Heat generated per second = V² / R Heat = (0.5)² / (3*10^14)

Heat = 0.25 / 3*10^14

Heat = 8.33*10^-16 Watt

Therefore, the rate at which heat is generated is 8.33*10^-16 Watt

4 0
4 years ago
Other questions:
  • An electron and a proton are held on an x axis, with the electron at x = + 1.000 m and the proton at x = - 1.000 m.how much work
    5·1 answer
  • What particle moves around the nucleus and has a negative charge??
    8·1 answer
  • What situation primarily involves heat transfer by convection?
    6·2 answers
  • A simple harmonic oscillator has amplitude 0.43 m and period 3.9 sec. What is the maximum acceleration?
    6·2 answers
  • Which property of gases best explains the ability of air bags to cushion the force of impact during a car accident?
    10·1 answer
  • A sled of mass 8 kg slides along the ice. It has an initial speed of 4 m/s but
    7·1 answer
  • List three ways in which decreasing the need to mine gold and reducing its harmful environmental effects. (Core Case Study) coul
    11·1 answer
  • It’s your birthday, and to celebrate you’re going to make your first bungee jump. You stand on a bridge 100 m above a raging riv
    11·1 answer
  • What evidence did wegener have to support his theory of plate tectonics?
    15·1 answer
  • Which items did Mendeleev write down on note cards while he was observing
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!