Answer:
the period T of whole motion should be twice the value for half at he bottom so T is 0.2sec.
w is angular frequency
formula:2π/T
now k is spring constant
F/R-->mw²
putting values:70*(2π/0.2)²
=4.9x10⁶
so we can say that SHM is not affected by the amplitude of the bounce.
Answer: did you get the answers?
Explanation:
Answer:
(A) 14.7 N
(B) 0.15 m
(C) the speed will become 24.8 m/s while wavelength becomes 0.21 m
Explanation:
frequency (f) = 120 Hz
mass (m) = 1.5 kg
linear mass density (μ) = 0.0480 kg/m
acceleration due to gravity (g) = 9.8 m/s^{2}
(A) tension on the rope (T) = mg = 1.5 x 9.8 = 14.7 N
speed =
speed =
speed = 17.5 m/s
(B) wavelength = velocity / frequency
wavelength = 17.5 / 120 = 0.15 m
(C) when the mass are increased to 3.00 kg
tension now becomes = mg = 3 x 9.8 = 29.4 N
therefore speed = = = 24.8 m/s
wavelength now becomes = velocity / frequency = 24.8 / 120 = 0.21 m
hence the speed will become 24.8 m/s while wavelength becomes 0.21 m
To solve this problem we will apply the concepts related to the final volume of a body after undergoing a thermal expansion. To determine the temperature, we will use the given relationship as well as the theoretical value of the volumetric coefficient of thermal expansion of copper. This is, for example to the initial volume defined as , the relation with the final volume as
Initial temperature =
Let T be the temperature after expanding by the formula of volume expansion
we have,
Where is the volume coefficient of copper
Therefore the temperature is 53.06°C