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3 years ago

Help asap please I will give you 5stars

Physics

1 answer:

boyakko [2]3 years ago

6 0

Explanation:

In the parallel combination, the equivalent resistance is given by :

$\dfrac{1}{R}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+....$

4. When three 150 ohms resistors are connected in parallel, the equivalent is given by :

$\dfrac{1}{R}=\dfrac{1}{150}+\dfrac{1}{150}+\dfrac{1}{150}\\\\R=50\ \Omega$

5. Three resistors of 20 ohms, 40 ohms and 100 ohms are connected in parallel, So,

$\dfrac{1}{R}=\dfrac{1}{20}+\dfrac{1}{40}+\dfrac{1}{100}\\\\=11.76\ \Omega$

Hence, this is the required solution.

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William WangHomework #33 Regents Review (3)0989Assignment Mode : Open (Time On Task) 9 of 25 ListenDuring a collision, an 84-kil

Lemur [1.5K]

Answer:

$1.7\cdot 10^3 N$

Explanation:

The impulse theorem states that the product between the force and the time interval of the collision is equal to the change in momentum:

$F \Delta t = m \Delta v$

where

F is the force

$\Delta t$ is the time interval

m is the mass

$\Delta v$ is the change in velocity

Here we have

m = 84 kg

$\Delta t = 1.2 s$

$\Delta v = 24 m/s$

So we can solve the equation to find the force:

$F= \frac{m \Delta v}{\Delta t }=\frac{(84 kg)(24 m/s)}{1.2 s}=1680 N \sim 1.7\cdot 10^3 N$

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2 years ago

Suppose an acorn with a mass of 3.17 g falls off a tree. At a particular moment during the fall, the acorn has a kinetic energy

denis-greek [22]

Potential and kinetic energy both decrease with the acorn's falling potential and kinetic energy.

The acorn's potential energy is at its peak when it reaches the top of the tree, yet its kinetic energy is zero (i.e., it is not accelerating).

The height of the ball reduces along with the potential energy as the acorn tumbles down the tree, but the kinetic energy rises (energy due to motion)

The height will be 0 and the kinetic and potential energy will be zero at the ground. This demonstrates that as an item falls, both potential and kinetic energy are lost.

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1 year ago

What is tan -1 (0.52)?

leva [86]

Answer:

-0.80985201682

Explanation:

Couldn't you have used Google???

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3 years ago

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inn [45]

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2 years ago

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galben [10]

The position of the centre of gravity of an object affects its stability. The lower the centre of gravity (G) is, the more stable the object. The higher it is the more likely the object is to topple over if it is pushed. Racing cars have really low centres of gravity so that they can corner rapidly without turning over.

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2 years ago