Answer:
Explanation:
Brownian motion is a random (irregular) motion of particles e.g smoke particle. The set up in the diagram can be used to observe the motion of smoke.
1. The apparatus used are:
A is a source of light
B is a converging lens
C is a glass smoke cell
D is a microscope
2. The uses of the apparatus are:
A - produces the light required to so as to see clearly the movement of the particles.
B - converges the rays of light from the source to the smoke cell.
C - is made of glass and used for encamping the smoke particles so as not to mix with air.
D - is used for the clear view or observation or study of the motion of the smoke particles in the cell.
Answer:
Explanation:
String theory proposes that the fundamental constituents of the universe are one-dimensional “strings” rather than point-like particles. String theory also requires six or seven extra dimensions of space, and it contains ways of relating large extra dimensions to small ones. In statistical mechanics, entropy is an extensive property of a thermodynamic system. It quantifies the number Ω of microscopic configurations that are consistent with the macroscopic quantities that characterize the system theyre related It later developed into superstring theory, which posits a connection called supersymmetry between bosons and the class of particles called fermions. Five consistent versions of superstring theory were developed before it was conjectured in the mid-1990s that they were all different limiting cases of a single theory in 11 dimensions known as M-theory. In late 1997, theorists discovered an important relationship called the AdS/CFT correspondence, which relates string theory to another type of physical theory called a quantum field theory.
Answer:
![2.09\ \text{m/s}](https://tex.z-dn.net/?f=2.09%5C%20%5Ctext%7Bm%2Fs%7D)
![22298.4\ \text{J}](https://tex.z-dn.net/?f=22298.4%5C%20%5Ctext%7BJ%7D)
Explanation:
m = Mass of each the cars = ![1.6\times 10^4\ \text{kg}](https://tex.z-dn.net/?f=1.6%5Ctimes%2010%5E4%5C%20%5Ctext%7Bkg%7D)
= Initial velocity of first car = 3.46 m/s
= Initial velocity of the other two cars = 1.4 m/s
v = Velocity of combined mass
As the momentum is conserved in the system we have
![mu_1+2mu_2=3mv\\\Rightarrow v=\dfrac{u_1+2u_2}{3}\\\Rightarrow v=\dfrac{3.46+2\times 1.4}{3}\\\Rightarrow v=2.09\ \text{m/s}](https://tex.z-dn.net/?f=mu_1%2B2mu_2%3D3mv%5C%5C%5CRightarrow%20v%3D%5Cdfrac%7Bu_1%2B2u_2%7D%7B3%7D%5C%5C%5CRightarrow%20v%3D%5Cdfrac%7B3.46%2B2%5Ctimes%201.4%7D%7B3%7D%5C%5C%5CRightarrow%20v%3D2.09%5C%20%5Ctext%7Bm%2Fs%7D)
Speed of the three coupled cars after the collision is
.
As energy in the system is conserved we have
![K=\dfrac{1}{2}mu_1^2+\dfrac{1}{2}2mu_2^2-\dfrac{1}{2}3mv^2\\\Rightarrow K=\dfrac{1}{2}\times 1.6\times 10^4\times 3.46^2+\dfrac{1}{2}\times 2\times 1.6\times 10^4\times 1.4^2-\dfrac{1}{2}\times 3\times 1.6\times 10^4\times 2.09^2\\\Rightarrow K=22298.4\ \text{J}](https://tex.z-dn.net/?f=K%3D%5Cdfrac%7B1%7D%7B2%7Dmu_1%5E2%2B%5Cdfrac%7B1%7D%7B2%7D2mu_2%5E2-%5Cdfrac%7B1%7D%7B2%7D3mv%5E2%5C%5C%5CRightarrow%20K%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%201.6%5Ctimes%2010%5E4%5Ctimes%203.46%5E2%2B%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%202%5Ctimes%201.6%5Ctimes%2010%5E4%5Ctimes%201.4%5E2-%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%203%5Ctimes%201.6%5Ctimes%2010%5E4%5Ctimes%202.09%5E2%5C%5C%5CRightarrow%20K%3D22298.4%5C%20%5Ctext%7BJ%7D)
The kinetic energy lost during the collision is
.
Answer:
![1.1\cdot 10^{-10}C](https://tex.z-dn.net/?f=1.1%5Ccdot%2010%5E%7B-10%7DC)
Explanation:
The electric field produced by a single point charge is given by:
![E=k\frac{q}{r^2}](https://tex.z-dn.net/?f=E%3Dk%5Cfrac%7Bq%7D%7Br%5E2%7D)
where
k is the Coulomb's constant
q is the charge
r is the distance from the charge
In this problem, we have
E = 1.0 N/C (magnitude of the electric field)
r = 1.0 m (distance from the charge)
Solving the equation for q, we find the charge:
![q=\frac{Er^2}{k}=\frac{(1.0 N/c)(1.0 m)^2}{9\cdot 10^9 Nm^2c^{-2}}=1.1\cdot 10^{-10}C](https://tex.z-dn.net/?f=q%3D%5Cfrac%7BEr%5E2%7D%7Bk%7D%3D%5Cfrac%7B%281.0%20N%2Fc%29%281.0%20m%29%5E2%7D%7B9%5Ccdot%2010%5E9%20Nm%5E2c%5E%7B-2%7D%7D%3D1.1%5Ccdot%2010%5E%7B-10%7DC)