Answer:
Ii is the circuit overload
Explanation:
Given :
The distance between a point charge and a neutral atom and is multiplied by a factor of 5.
To Find :
By what factor does the force on the neutral atom by the point charge change.
Solution :
We know, electrostatic force between two object is directly proportional to product of charge and inversely proportional to distance between them.
Now, charge in neutral atom is 0 C.
So, the electrostatic force between two of them is also 0 N.
Therefore, by changing distance between the charge the forces did no change ( it remains zero).
<u>Answer:</u> The volume of solution that was used is 271.08 mL
<u>Explanation:</u>
The relationship between specific gravity and density of a substance is given as:
We are given:
Specific gravity of water = 0.830
Density of water = 1.00 g/mL
Putting values in above equation we get:
To calculate the volume of solution, we use the equation:
Density of solution = 0.830 g/mL
Mass of solution = 225 g
Putting values in above equation, we get:
Hence, the volume of solution that was used is 271.08 mL
Answer: 23.53g
Explanation:
5.2/(2x16) = 0.1625 mol
0.1625 x 2 = 0.325 mol
0.325 x (23 x 2 + 16 x 2) = 78 x 0.325 = 23.53g
<h3>
Answer:</h3>
3.072 L
<h3>
Explanation:</h3>
<u>We are given;</u>
- Initial pressure, P₁ = 345 torr
- Initial temperature,T₁ = -15°C
But, K = °C + 273
= -15°C + 273
= 258 K
- Initial volume, V₁ =3.48 L
- Final pressure, P₂ = 468 torr
- Final temperature, T₂ = 36°C
= 36 °C + 273
= 309 K
We are required to calculate the new volume, V₂
- Using the combined gas law;
P₁V₁/T₁ = P₂V₂/T₂
- We can calculate the new volume, V₂;
- Rearranging the formula;
V₂ =(P₁V₁T₂) ÷ (T₁P₂)
= (345 torr × 3.48 L × 309 K) ÷ (258 K × 468 torr)
= 3.072 L
Therefore, the new volume of the sample is 3.072 L
