Question

As blood passes through the capillary bed in an organ, the capillaries join to form venules (small veins). If the blood speed increases by a factor of 4.00 and the total cross-sectional area of the venules is 10.0 cm2 , what is the total cross-sectional area of the capillaries feeding these venules? (b) How many capillaries are involved if their average diameter is 10.0 µm?

Answer 1

Answer:

capillaries are 5.09 × $10^{7}$

Explanation:

Given data

area = 10.0 cm2

speed = 4.00

average diameter = 10.0 µm

to find out

total cross-sectional area and How many capillaries

solution

we apply here continuity equation

a1× v1  =a2 ×v2

we know v2 /v1 = a1/a2 that is equal 4

so here a1 will be

= 4 × 10

so a1 is 40 cm²

and capillaries are a1/ area

area = $\pi$ /4 × 10 ² ×$10^{-12}$

capillaries are = 40 ×$10^{-4}$ /  $\pi$ /4 × 10 ² ×$10^{-12}$

capillaries are 5.09 × [tex]10^{7}