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Daniel [21]
3 years ago
10

Gina is driving her car to work, but she’s stopped at a red light. When the light turns green, she presses the gas pedal and acc

elerates (speeds up) to move the car. Which of these statements is true the moment Gina presses the gas pedal? Assume the road is flat and level. A. The net force on the car is zero in the horizontal direction. B. The net force on the car is zero in the horizontal and the vertical directions. C. The net force on the car is greater than zero in the horizontal direction. D. The net force on the car is greater than zero in the vertical direction. E. The net force on the car is less than zero in the vertical direction.
Physics
1 answer:
Vlad [161]3 years ago
4 0

Since car is initially at rest so at that position the net force on car in vertical as well as horizontal both direction is zero

but after lights are green the car will speed up in horizontal direction

so now we can say that

It will accelerate in horizontal direction

So now as per Newton's formula we have

F = ma

so now the force in horizontal direction will become nonzero while in vertical direction car is still in equilibrium

So now we can say

F_x = ma

F_y = 0

so the correct answer will be

C. The net force on the car is greater than zero in the horizontal direction.

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A projectile has an initial horizontal velocity of 15 meters per second and an initial vertical velocity of 25 meters per second
Artyom0805 [142]

Answer:

75 m

Explanation:

The horizontal motion of the projectile is a uniform motion with constant speed, since there are no forces acting along the horizontal direction (if we neglect air resistance), so the horizontal acceleration is zero.

The horizontal component of the velocity of the projectile is

v_x = 15 m/s

and it is constant during the motion;

the total time of flight is

t = 5 s

Therefore, we can apply the formula of the uniform motion to find the horizontal displacement of the projectile:

d= v_x t =(15 m/s)(5 s)=75 m

5 0
3 years ago
A 0.050 kg bullet strikes a 5.0 kg wooden block with a velocity of 909 m/s and embeds itself in the block which fies off its sta
serg [7]

Answer:

The final velocity of the bullet is 9 m/s.

Explanation:

We have,

Mass of a bullet is, m = 0.05 kg

Mass of wooden block is, M = 5 kg

Initial speed of bullet, v = 909 m/s

The bullet embeds itself in the block which flies off its stand. Let V is the final velocity of the bullet. The this case, momentum of the system remains conserved. So,

mv=(m+M)V\\\\V=\dfrac{mv}{m+M}\\\\V=\dfrac{0.05\times 909}{0.050+5}\\\\V=9\ m/s

So, the final velocity of the bullet is 9 m/s.

5 0
3 years ago
The apparent weight of a student in alift is 564N . if the mass of the student is 60.3kg, what is the acceleration of the lift ?
Yuki888 [10]

Answer:

-.457 m/s^2

Explanation:

Actual weight =   60 .3 (9.81) = 591.54 N

Accel of lift changes this to    60.3 ( 9.81 - L)     where L - accel of lift

                                           60.3 ( 9.81 - L ) = 564

                                               solve for L = .457 m/s^2  DOWNWARD

                                                        so L = - .457 m/s^2

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2 years ago
Need help asap; put you as brainliest​
Vera_Pavlovna [14]

Answer:

unmmmmmmmm I think the answerA

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2 years ago
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ICE Princess25 [194]
The first one is dependent variable
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