All categories

3 years ago

How is an image formed by a plane mirror?

2 answers:

7 0

The image formed by a plane mirror is always virtual (meaning that the light rays do not actually come from the image), upright, and of the same shape and size as the object it is reflecting.

nikitadnepr [17]3 years ago

4 0

Answer:

Light bounces off of the mirror and then appears to come from behind the mirror.

Explanation:

You might be interested in

A particle with charge 7.76×10^(−8)C is moving in a region where there is a uniform 0.700 T magnetic field in the +x-direction.

kodGreya [7K]

Answer:

The z-component of the force is $\= F_z = 0.00141 \ N$

Explanation:

From the question we are told that

The charge on the particle is $q = 7.76 *0^{-8} \ C$

The magnitude of the magnetic field is $B = 0.700\r i \ T$

The velocity of the particle toward the x-direction is $v_x = -1.68*10^{4}\r i \ m/s$

The velocity of the particle toward the y-direction is

$v_y = -2.61*10^{4}\ \r j \ m/s$

The velocity of the particle toward the z-direction is

$v_y = -5.85*10^{4}\ \r k \ m/s$

Generally the force on this particle is mathematically represented as

$\= F = q (\= v X \= B )$

So we have

$\= F = q ( v_x \r i + v_y \r j + v_z \r k ) \ \ X \ ( \= B i)$

$\= F = q (v_y B(-\r k) + v_z B\r j)$

substituting values

$\= F = (7.7 *10^{-8})([ (-2.61*10^{4}) (0.700)](-\r z) + [(5.58*10^{4}) (0.700)]\r y)$

$\= F= 0.00303\ \r j +0.00141\ \r k$

So the z-component of the force is $\= F_z = 0.00141 \ N$

Note : The cross-multiplication template of unit vectors is shown on the first uploaded image ( From Wikibooks ).

7 0

3 years ago

Can someone please answer this for me

UNO [17]

Because in my opinion they do bending of a light wave as it passes at an angle from one medium to another.

5 0

3 years ago

What is the control group

kolbaska11 [484]

Answer: the group in an experiment that doesn’t get treatment

Explanation:

8 0

2 years ago

What does the term calorie refer to

OLga [1]

Hey there,
It means- the amount of energy required to raise the temperature of a liter of water one degree centigrade at sea level

Hope this helps :))

~Top

6 0

3 years ago

A person kicks a ball off of a 50m high cliff with a speed of 10 m/s. How long will it take the ball to hit the ground? * 7 poin

Musya8 [376]

Presumably, the ball is kicked parallel to the ground below the cliff, so its altitude y at time t is

$y(t)=50\,\mathrm m-\dfrac12gt^2$