To find the answer, plot down the factors for every number.
12: 1, 2 ,3 ,4, 6, 12
18: 1, 2, 3, 6, 9, 18
84: 1, 2, 3, 4, 6, 7, 12
If you noticed, the number that was common to the 3 numbers, were 1, 2, 3, and 6
And 6 is the bigger number
So 6 is your GCF
Answer:
Explanation:
For spring
where n is frequency of oscillation and k is force constant and m is mass
Putting the values
k = .4032 N/m
F= k x
where F is force , k is force constant and x is extension
Putting the given values
1 = .4032 x
x = 2.48 m
Answer:
The distance between the places where the intensity is zero due to the double slit effect is 15 mm.
Explanation:
Given that,
Distance between the slits = 0.04 mm
Width = 0.01 mm
Distance between the slits and screen = 1 m
Wavelength = 600 nm
We need to calculate the distance between the places where the intensity is zero due to the double slit effect
For constructive fringe
First minima from center
Second minima from center
The distance between the places where the intensity is zero due to the double slit effect
Put the value into the formula
Hence, The distance between the places where the intensity is zero due to the double slit effect is 15 mm.
Answer:
F = 592238.09 N
Explanation:
To find the mean force you first calculate the acceleration by using the following kinematic equation:
you do "a" the subject of the equation and replace the values of the other parameters:
next, the force, by using the second Newton law is:
hence, the force is 592238.09 N
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TRANSLATION:
Para encontrar a força média, primeiro calcule a aceleração usando a seguinte equação cinemática:
você faz "a" o assunto da equação e substitui os valores dos outros parâmetros:
Em seguida, a força, usando a segunda lei de Newton, é:
portanto, a força é 592238.09 N
Answer:
0.09kg of air
Explanation:
The dimensions of the room are given
change the height to meters by dividing it by thousand.
For the volume multiplying the length,width and height (all should be in the same unit most suitable being meters).
Volume refers to the amount of space inside a box or a object.
The amount of air is equal to the volume.