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otez555 [7]
3 years ago
11

Em um centro de distribuição uma empilhadeira carrega uma caixa de 1000kg até o caminhão responsável pelo transporte desta carga

. Partindo do repouso a empilhadeira precisa percorrer uma certa distância 8,4 m para atingir a sua velocidade máxima de operação 10 k/h. Determine a força média necessária para acelerar essa carga.
Physics
1 answer:
Yakvenalex [24]3 years ago
8 0

Answer:

F = 592238.09 N

Explanation:

To find the mean force you first calculate the acceleration by using the following kinematic equation:

v^2=v_o^2+2ax\\\\v_o=0m/s\\\\v=10km/h\\\\x=8.4m\\\\

you do "a" the subject of the equation and replace the values of the other parameters:

a=\frac{v^2}{2x}=\frac{10000m/s}{2(8.4m)}=595.23\frac{m}{s^2}

next, the force, by using the second Newton law is:

F=ma=(1000kg)(595.23\frac{m}{s^2})=595238.09\ N

hence, the force is 592238.09 N

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TRANSLATION:

Para encontrar a força média, primeiro calcule a aceleração usando a seguinte equação cinemática:

você faz "a" o assunto da equação e substitui os valores dos outros parâmetros:

Em seguida, a força, usando a segunda lei de Newton, é:

portanto, a força é 592238.09 N

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