Answer:
116.7 Hz
Explanation:
Let there are two wires A and B.
Tension in wire A = T
Tension in wire B = 2T
Length of wire A = L
Length of wire B = 2L
fundamental frequency in wire A, fA = 330 Hz
let the fundamental frequency in wire B is fB.
The formula for the fundamental frequency is given by
where, μ is the mass per unit length
mass per unit length of wire A = Area of wire A x density
mass per unit length of wire B = Area of wire B x density
So,
fB = 330 / 2.828
fB = 116.7 Hz
Thus, the frequency in the second wire is 116.7 Hz.
Answer:
b) n = 1 to n = 4.
Explanation:
a ) n = 4 to n = 1 transition represents release of energy because transition is from high energy orbit to low energy orbit.
Similarly c) n = 2 to n = 1 represents release of energy because transition is from high energy to low energy orbit.
d ) n = 1 to n = 3 is also energy absorbing transition but amount of energy absorbed is less as compared with option b) transition .
So the correct option is b)
Im not sure but i think its 4ft
hope this helps
I feel like my answer is wrong but I think it B) false or C) true