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uranmaximum [27]
3 years ago
10

Jenny wants to determine if a new brand name washing detergent is better than her old detergent. She washes ten dirty t-shirts w

ith the new washing detergent and ten dirty t-shirts with the old detergent. Identify the dependent and independent variables for this experiment. Don't forget both the IV and DV in your answer!
Physics
1 answer:
zmey [24]3 years ago
6 0

The independent variable would be the shirts you are using the dependent variable would be the detergent.

Hope this helps!

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The volume of a cube is 512 cm3. What would change if the volume of the cube were measured in cubic meters?. . A.. The volume of
Black_prince [1.1K]
We are given with a volume of a cube equal to 512 cm3. In this case, when the volume is expressed to cubic meters, the volume will still stay the same but the number of cubic units would decrease. a centimeter is a smaller unit than a meter, hence the value given should be divided by 1 million to express to m3.
6 0
3 years ago
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Five lamp, each labbled "6V,3W" are operated at normal brightness. What is the total energy supplied to the lamps in five second
REY [17]

Answer:

E = 75 J

Explanation:

First, we will calculate the total power consumed by the five lamps:

Total\ Power = P = (5)(Power\ of\ one\ lamp)\\P = (5)(3\ W)\\P = 15\ W

Now, the energy supply can be calculated as follows:

E = Pt

where,

E = Energy = ?

t = time = 5 s

Therefore,

E = (15 W)(5 s)

<u>E = 75 J</u>

8 0
2 years ago
I meed help with these 2 questions plz
ludmilkaskok [199]

-- 30N

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3 years ago
What is the system that pumps blood throughout the body
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The human heart is an organ that pumps blood throughout the body via the circulatory system, supplying oxygen and nutrients to the tissues and removing carbon dioxide and other wastes.

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3 years ago
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The drawing shows an adiabatically isolated cylinder that is divided initially into two identical parts by an adiabatic partitio
Sveta_85 [38]

Answer:

temperature on left side is 1.48 times the temperature on right

Explanation:

GIVEN DATA:

\gamma = 5/3

T1 = 525 K

T2 = 275 K

We know that

P_1 = \frac{nRT_1}{v}

P_2 = \frac{nrT_2}{v}

n and v remain same at both side. so we have

\frac{P_1}{P_2} = \frac{T_1}{T_2} = \frac{525}{275} = \frac{21}{11}

P_1 = \frac{21}{11} P_2 ..............1

let final pressure is P and temp  T_1 {f} and T_2 {f}

P_1^{1-\gamma} T_1^{\gamma} = P^{1 - \gamma}T_1 {f}^{\gamma}

P_1^{-2/3} T_1^{5/3} = P^{-2/3} T_1 {f}^{5/3} ..................2

similarly

P_2^{-2/3} T_2^{5/3} = P^{-2/3} T_2 {f}^{5/3} .............3

divide 2 equation by 3rd equation

\frac{21}{11}^{-2/3} \frac{21}{11}^{5/3} = [\frac{T_1 {f}}{T_2 {f}}]^{5/3}

T_1 {f} = 1.48 T_2 {f}

thus, temperature on left side is 1.48 times the temperature on right

6 0
3 years ago
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