Two pulleys, one with a radius 2R and one with a radius of R, are welded together and can rotate about the same axis. A block is
1 answer:
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Answer:
a) 0.138J
b) 3.58m/S
c) (1.52J)(I)
Explanation:
a) to find the increase in the translational kinetic energy you can use the relation
where Wp is the work done by the person and Wg is the work done by the gravitational force
By replacing Wp=Fh1 and Wg=mgh2, being h1 the distance of the motion of the hand and h2 the distance of the yo-yo, m is the mass of the yo-yo, then you obtain:
the change in the translational kinetic energy is 0.138J
b) the new speed of the yo-yo is obtained by using the previous result and the formula for the kinetic energy of an object:
where vf is the final speed, vo is the initial speed. By doing vf the subject of the formula and replacing you get:
the new speed is 3.58m/s
c) in this case what you can compute is the quotient between the initial rotational energy and the final rotational energy
hence, the change in Er is about 1.52J times the initial rotational energy
Answer:
a)
b)
Explanation:
From the exercise we got the ball's equation of position:
a) To find the average velocity at the given time we need to use the following formula:
Being said that, we need to find the ball's position at t=2, t=2.5, t=2.1, t=2.01, t=2.001
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b) To find the instantaneous velocity we need to derivate the equation