Question

Aqueous copper (ll) sulfate reacts with solid iron metal to produce aqueous iron (ll) sulfate and solid copper metal

Answer 1

Answer:

$CuSO_4 (aq) + Fe (s)\rightarrow FeSO_4 (aq) + Cu (s)$

Explanation:

Identify all of the compounds present:

• aqueous copper(II) sulfate: we have copper charged as 2+, sulfate anion has a charge of 2-. This means the charges are balanced if we take 1 ion of each to give $CuSO_4 (aq)$;
• solid iron metal: iron metal is Fe, then including the state of iron, we have $Fe (s)$;
• aqueous iron(II) sulfate: iron has a charge of 2+, sulfate has a charge of 2-, so the positive charge balances the negative charge to give a formula of $FeSO_4 (aq)$;
• solid copper metal: copper metal is Cu, then including the state of copper, we have $Cu (s)$.

We then have a reaction:

$CuSO_4 (aq) + Fe (s)\rightarrow FeSO_4 (aq) + Cu (s)$