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Arisa [49]
3 years ago
6

Caluclate the number of grams of oxygen that must react

Chemistry
1 answer:
bonufazy [111]3 years ago
8 0

Answer : The number of grams of oxygen react must be, 170.4 grams.

Solution : Given,

Mass of C_3H_8 = 46.85 g

Molar mass of C_3H_8 = 44 g/mole

Molar mass of O_2 = 32 g/mole

First we have to calculate the moles of C_3H_8.

\text{ Moles of }C_3H_8=\frac{\text{ Mass of }C_3H_8}{\text{ Molar mass of }C_3H_8}=\frac{46.85g}{44g/mole}=1.065moles

Now we have to calculate the moles of O_2

The balanced chemical reaction is,

C_3H_8+5O_2\rightarrow 3CO_2+4H_2O

From the balanced reaction we conclude that

As, 1 mole of C_3H_8 react with 5 mole of O_2

So, 1.065 moles of C_3H_8 react with 1.065\times 5=5.325 moles of O_2

Now we have to calculate the mass of O_2

\text{ Mass of }O_2=\text{ Moles of }O_2\times \text{ Molar mass of }O_2

\text{ Mass of }O_2=(5.325moles)\times (32g/mole)=170.4g

Therefore, the number of grams of oxygen react must be, 170.4 grams.

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