<span>A red ladybug appears red in white light, red in red light, and black in blue light.
When a ladybug is red it means that its shell reflects the red light, or the radiation between 650-700 nm, from the visible spectrum. A white light is composed of all colours, the whole visible spectrum, therefore, the ladybug shell will reflect the red colour. When considering a red light over a red ladybug, the ladybug will again appear red because the spectrum in which there is reflection of colour from its shell is present. On the other hand, when blue light is put over a red ladybug, the ladybug will appear black as there is no light that its shell can reflect.</span>
A 5kg backpack will weigh 49 newtons on earth
Answer:
a. 4.733 × 10⁻¹⁹ J = 2.954 eV b i. yes ii. 0.054 eV = 8.651 × 10⁻²¹ J
Explanation:
a. Find the energy of the incident photon.
The energy of the incident photon E = hc/λ where h = Planck's constant = 6.626 × 10⁻³⁴ Js, c = speed of light = 3 × 10⁸ m/s and λ = wavelength of light = 420 nm = 420 × 10⁻⁹ m
Substituting the values of the variables into the equation, we have
E = hc/λ
= 6.626 × 10⁻³⁴ Js × 3 × 10⁸ m/s ÷ 420 × 10⁻⁹ m
= 19.878 × 10⁻²⁶ Jm ÷ 420 × 10⁻⁹ m
= 0.04733 × 10⁻¹⁷ J
= 4.733 × 10⁻¹⁹ J
Since 1 eV = 1.602 × 10⁻¹⁹ J,
4.733 × 10⁻¹⁹ J = 4.733 × 10⁻¹⁹ J × 1 eV/1.602 × 10⁻¹⁹ J = 2.954 eV
b. i. Is this energy enough for an electron to leave the atom
Since E = 2.954 eV is greater than the work function Ф = 2.9 eV, an electron would leave the atom. So, the answer is yes.
ii. What is its maximum energy?
The maximum energy E' = E - Ф = 2.954 - 2.9
= 0.054 eV
= 0.054 × 1 eV
= 0.054 × 1.602 × 10⁻¹⁹ J
= 0.08651 × 10⁻¹⁹ J
= 8.651 × 10⁻²¹ J
ببيع ما عندي رصيد انا ما في رصيد شي عندي شغل رصيد انا ما في شي ما عندي عندي شي عندي شغل عنما في رصيد عندي
Answer: A. Digital images can be easily removed from a storage device or lost
Explanation:
I solved it in study island ( sometimes you need to have trust)