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3 years ago

PLEASE HELP ME ASAPPPPP What is the density of a piece of cardboard that has a mass of 250 g and volume of 46 mL? *

Chemistry

1 answer:

Roman55 [17]3 years ago

6 0

Answer:

The answer is

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass = 250 g

volume = 46 mL

The density is

$density = \frac{250}{46} \\ = 5.4347826...$

We have the final answer as

Hope this helps you

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Consider the element carbon. How many electrons can be found in a carbon atom? How many are valence electrons?

Eva8 [605]

Answer:

option B= 6 : 4

Explanation:

Properties:

1. Carbon have six electron and six proton.

2. The two electrons are present in first shell while remaining of four electrons are present in the second shell.

3. it is non-metallic element and present in the group fourteen of periodic table.

4. its atomic mass is 12.0107 u.

5. its melting and boiling point is 3550 °C and 4827 °C respectively.

Uses:

1. it is used as a fuel in the form of coal.

2. in the form of graphite it is used in dry cells, as a lubricant, in pencil and high temperature crucible.

3. it is also used in jewelry in the form of diamond and because of its hard nature used in industries for drilling, polishing, cutting and grinding.

4. carbon black powder is used in printer ink.

5. its most common alloy with iron is steel.

6. it form variety of compound with number of other elements like nitrogen, hydrogen, oxygen etc.

Electronic configuration:

1s2, 2s2, 2p2

Isotopes of carbon:

There are fifteen isotopes of carbon from C8 - C22. The isotopes C12 and C13 are stable while C14 is radioactive.

4 0

3 years ago

The formation of SO3 from SO2 and O2 is an intermediate step in the manufacture of sulfuric acid, and it is also responsible for

jeka57 [31]

Answer:

118.22 atm

Explanation:

2SO₂(g) + O₂(g) ⇌ 2SO₃(g)

KP = 0.13 = $\frac{p(SO_{3})^{2}}{p(SO_{2})^{2}p(O_{2})}$

Where p(SO₃) is the partial pressure of SO₃, p(SO₂) is the partial pressure of SO₂ and p(O₂) is the partial pressure of O₂.

With 2.00 mol SO₂ and 2.00 mol O₂ if there was a 100% yield of SO₃, then 2 moles of SO₃ would be produced and 1.00 mol of O₂ would remain.
With a 71.0% yield, there are only 2*0.71 = 1.42 mol SO₃, the moles of SO₂ that didn't react would be 2 - 1.42 = 0.58; and the moles of O₂ that didn't react would be 2 - 1.42/2 = 1.29.

The total number of moles is 1.42 + 0.58 + 1.29 = 3.29. With that value we can calculate the molar fraction (X) of each component:

XSO₂ = 0.58/3.29 = 0.176

XO₂ = 1.29/3.29 = 0.392

XSO₃ = 1.42/3.29 = 0.432

The partial pressure of each gas is equal to the total pressure (PT) multiplied by the molar fraction of each component.

p(SO₂) = 0.176 * PT

p(O₂) = 0.392 * PT

p(SO₃) = 0.432 * PT

Rewriting KP and solving for PT:

$\frac{p(SO_{3})^{2}}{p(SO_{2})^{2}p(O_{2})}=0.13\\\frac{(0.432*P_{T})^{2}}{(0.176*P_{T})^{2}(0.392*P_{T})} =0.13\\\frac{0.1866*P_{T}^{2}}{0.0121*P_{T}^{3}} =0.13\\\frac{15.369}{P_{T}}=0.13\\P_{T}=118.22 atm$

5 0

3 years ago

Answer ASAP pls

Komok [63]

Answer:

wavelengths

Explanation:

4 0

2 years ago

I need help with these two if you zoom in it’s clearer

makvit [3.9K]

Answer:

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3 0

2 years ago

Balance the following chemical equations

jok3333 [9.3K]

Answer:

2N2 + O2 ⇒ 2N2O

Explanation:

Since I cannot see the product's of the second chemical equation I will only solve the first one.

In order to balance a chemical equation you need to make sure that the atoms on both sides are equal.

In this case we have...

N2 + O2 = N2O

N = 2

O = 2

N = 2

O = 2

Change the coefficient:

N2O = 2N20

2 × 2 = 4

1 × 2 = 2

2N2 + O2 ⇒ 2N2O

Hope this helps.

4 0

2 years ago