Answer:
I'm pretty sure this is a question about your opinion so there is no wrong answer! Just think about the question and if you were in those shoes. There is no right or wrong answer! :)
Explanation:
Special properties of water are its high heat capacity and heat of vaporization, its ability to dissolve polar molecules, its cohesive and adhesive properties, and its dissociation into ions that leads to generating pH. Understanding these characteristics of water helps to elucidate its importance in maintaining life.
Answer:
<u>B</u> What role do animals have in the carbon cycle?
Group of answer choices
use water and release oxygen
<u>use sugar and release carbon</u>
use carbon and release oxygen
use carbon and release nitrogen
<u>D, E</u> Select TWO statements that describe what the scientists will observe in the ecosystem after fossil fuels have been extracted and burned.
Group of answer choices
There is more available space for carbon to become fossil fuels.
There is less carbon in storage.
There will be less carbon in the water.
<u>There is more carbon in the atmosphere.</u>
<u>There will be more carbon respired by organisms.</u>
There will be less carbon released through decomposition.
Explanation:
Animals obtain energy through sugar from the food they eat and release carbon into the air through respiration. Therefore, they partake in the carbon cycle by using sugar and releasing energy.
As far as the second question, when fossil fuels are burned, the carbon contained within them is released into the atmosphere in the form of carbon dioxide. So, there will obviously be a greater amount in the atmosphere.
I would like to apologise in advance if either of my option choices were incorrect.
Answer:
ΔG° = -133,1 kJ
Explanation:
For the reactions:
<em>(1) </em>V₂O₃(s) + 3CO(g) → 2V(s) + 3CO₂(g); ΔH° = 369,8 kJ; ΔS° = 8,3 J/K
<em>(2) </em>V₂O₅(s) + 2CO(g) → V₂O₃(s) + 2CO₂(g); ΔH° = –234,2 kJ; ΔS° = 0,2 J/K
By Hess's law it is possible to obtain the ΔH° and ΔS° of:
2V(s) + 5CO₂(g) → V₂O₅(s) + 5CO(g)
Substracting -(1)-(2), that means:
ΔH° = -369,8 kJ - (-234,2 kJ) = <em>-135,6 kJ</em>
ΔS° = - 8,3 J/K - 0,2 J/K =<em> -8,5 J/K</em>
Using: ΔG° = ΔH° - TΔS° at 298K
ΔG° = -135,6 kJ - 298K×-8,5x10⁻³kJ/K
<em>ΔG° = -133,1 kJ</em>
I hope it helps!