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erik [133]
3 years ago
14

What is 3/4 of a year ? Write in months.

Mathematics
2 answers:
notsponge [240]3 years ago
7 0
Hi there!

To make this a bit simpler, first, we should convert a year into months:

1 yr = 12 mo

Now, we multiply 12 by 3/4, since we're trying to find 3/4 of a year. 

12 * 3/4 = 9

So, our answer would be 9 months.

Hope this helps!
SIZIF [17.4K]3 years ago
6 0
9 months because 4/4 is 12 months. 1/4 is 3 months and you do 3 x 1/= 3/4 and then doo 3 times 3 = 9
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Step-by-step explanation:

lets say the dimensions are x and y. we have x*y=162, and 2x+2y=54. from the second equation we have x+y=27 so y=27-x. plug this into the first equation to get x(27-x)=162 or -x^2 + 27x = 162. x^2 - 27x + 162 = 0. simplify to get (x-18)(x-9)=0. so x=18 or x=9. when x=18, y=9, when x=9, y=18 so the dimensions are 18 by 9 meters

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The amount of salt in the tank changes with rate according to

Q'(t)=\left(1\dfrac{\rm lb}{\rm gal}\right)\left(4\dfrac{\rm gal}{\rm min}\right)-\left(\dfrac{Q(t)}{300+(4-1)t}\dfrac{\rm lb}{\rm gal}\right)\left(1\dfrac{\rm gal}{\rm min}\right)

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(300+3t)^{1/3}Q'+(300+3t)^{-2/3}Q=4(300+3t)^{1/3}

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\big((300+3t)^{1/3}Q\big)'=4(300+3t)^{1/3}

Integrate both sides and solve for Q(t) to get

(300+3t)^{1/3}Q=(300+3t)^{4/3}+C

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Given that Q(0)=100, we find

100=300+C\cdot300^{-1/3}\implies C=-200\cdot300^{1/3}

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Q(t)=300+3t-200\cdot300^{1/3}(300+3t)^{-1/3}

\boxed{Q(t)=300+3t-2\cdot100^{4/3}(100+t)^{-1/3}}

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