Answer:
7.16 m /s
Explanation:
The depth of the small pipe attached with the side wall of tank from the surface of water
h =( 3.1 - .48 )m
= 2.62 m
velocity of flow of water= √ 2 g h
= √ 2 x 9.8 x 2.62
= 7.16 m /s
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Answer:
i. + 22.5 m ii. 4.0 m
Explanation:
i. Image distance
Using the lens formula
1/u + 1/v = 1/f where f = focal length = + 18.0 m, u = object distance = distance of shark away from lens = + 90.0 m and v = image distance from lens = unknown
So, we find v
1/v = 1/f - 1/u
= 1/+18 - 1/+90
= (5 - 1)/90
= 4/90
v = 90/4
= + 22.5 m
So the image is real and formed 22.5 m away on the other side of the lens.
ii Length of Shark
Using the magnification formula, m = image height/object height = image distance/object distance. image height = 1.0 m where object height = length of shark.
m = image distance/object distance
= v/u
= +22.5/+90
= 0.25
0.25 = image height/object height
So,
object height = image height/0.25
= 1.0 m/0.25
= 4.0 m
So, the length of the shark is 4.0 m
Explanation:
heat caoacity and heat is difference
Answer:
See below
Explanation:
a) 500 cm^3 * .90 gm/cm^3 = 450 gm of oil
b) 450 gm + 80 gm = 530 gm of oil and bottle
Answer:
b. calculate the constant force exerted on the pole vaulter due to the collision
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