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2 years ago

13

Is velocity related to momentum

2 answers:

MakcuM [25]2 years ago

7 0

Yes momentum is expressed as mass * velocity:

p = m * v

p: momentum
m: mass
v: velocity

enot [183]2 years ago

6 0

Yes
momentum=mass x velocity
or you could rearrange the formula to find velocity = momentum/mass (you get this by dividing both sides in the original equation by mass)
you could also get that mass= momentum/velocity (you get this by rearranging both sides of the original equation by velocity)

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What is the gravitational potential energy of a 3 kg ball kicked into the air at a height of 5 meters?

sladkih [1.3K]

formula for gravitational P.E =mgh

Solution:-mass=3kg height=5metre and gravity=9.8 or 10m/sec² so P.E=mgh , 3×9.8×5=147kgm²/sec²

7 0

2 years ago

A lawyer drives from her home, located 88 milesmiles east and 1818 milesmiles north of the town courthouse, to her office, lo

myrzilka [38]

Answer:

the distance between the lawyer's home and her office is 124 miles

Explanation:

given information:

first lets assume that

x-axis (west = positive, east = negative)

y-axis (north = positive, south = negative)

thus,

distance of the house = (-88,18)

distance of the office = (13, -54)

thus, the distance between the lawyer's home and her office

R = √(x₂ - x₁)² + (y₂ - y₁)²

= √(13 - (-88))² + (-54 -18)²

= 124 miles

7 0

3 years ago

archer shoots his arrow towards a target at a distance of 90 m, and hits ‘bullseye’ . Calculate the acceleration and time taken

Cerrena [4.2K]

Answer:

Acceleration = 45m/s^2
Time = 2 s

Explanation:

6 0

3 years ago

A (B + 25.0) g mass is hung on a spring. As a result, the spring stretches (8.50 A) cm. If the object is then pulled an addition

Morgarella [4.7K]

Answer:

Time period of the osculation will be 2.1371 sec

Explanation:

We have given mass m = (B+25)

And the spring is stretched by (8.5 A )

Here A = 13 and B = 427

So mass m = 427+25 = 452 gram = 0.452 kg

Spring stretched x= 8.5×13 = 110.5 cm

As there is additional streching of spring by 3 cm

So new x = 110.5+3 = 113.5 = 1.135 m

Now we know that force is given by F = mg

And we also know that F = Kx

So $mg=Kx$

$K=\frac{mg}{x}=\frac{0.452\times 9.8}{1.135}=3.90N/m$

Now we know that $\omega =\sqrt{\frac{K}{m}}$

So $\frac{2\pi }{T} =\sqrt{\frac{K}{m}}$

$\frac{2\times 3.14 }{T} =\sqrt{\frac{3.90}{0.452}}$

$T=2.1371sec$

8 0

2 years ago

Oduvanchick [21]

Answer:

the answer is different

Explanation:

i took the test

3 0

3 years ago