Answer:
The mass will stay the same throughout time
From the information given in the drawing, it's not possible
to tell whether the displacements are equal, because we
don't know what the vectors represent.
If the vectors are distances, then the displacements are not
equal, because the distance between the start and end points
are not equal.
If the vectors are speeds, then they don't tell us anything about
the distance between the start and end points, so we can't calculate
the displacements.
Answer:
Explanation:
For the simple pendulum problem we need to remember that:
,
where 
is the angular position, t is time, g is the gravity, and L is the length of the pendulum. We also need to remember that there is a relationship between the angular frequency and the length of the pendulum:
,
where 
is the angular frequency.
There is also an equation that relates the oscillation period and the angular frequeny:
,
where T is the oscillation period. Now, we can easily solve for L:
Answer:
S = V t where S is the horizontal distance traveled
1/2 g t^2 = H where H is the vertical distance traveled
t^2 = 2 H / g
V^2 = S^2 / t^2 = S^2 g / (2 H) combining equations
tan theta = H / S
V^2 = S g / (2 tan theta)
Using S = L cos theta
V^2 = L g cos theta / (2 tan theta)
Giving V in terms of L and theta
