Answer:
Explanation:
We shall apply law of conservation of momentum to know velocity after collision . Let it be v .
total momentum before collision = total momentum after collision
15 x 1.5 - 12 x .75 = ( 15 + 12 ) v
v = .5 m /s
kinetic energy before collision
1/2 x 15 x 1.5² + 1/2 x 12 x .75²
= 16.875 + 3.375
= 20.25 J
kinetic energy after collision
= 1/2 x ( 15 + 12 ) x .5²
= 3.375 J
Loss of energy = 16.875 J
This energy appear as heat and sound energy that is produced during collision .
Answer:
933. 3kg
Explanation:
We are given that
Mass,m=2000 kg
Initial speed,u=4.4 m/s
We have to find the maximum mass of grain if the speed of loaded freight car must not go below 3.0 m/s.
Final speed,v=3 m/s
By conservation of momentum
Initial momentum=Final momentum

Substitute the values



Mass of freight loaded car=2933.3 kg
Mass of grains=2933.3-2000=933.3 kg
Hence, the maximum mass of grains that it can accept=933.3 kg
Answer:
600
Explanation:
GPE=mgh (mass*gravitational force*height)
m=10 kg
g=10
h=6m
10*10*6= 600 Joules