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hichkok12 [17]
4 years ago
8

Explain what happens to the average kinetic energy, thermal energy, and temperature of a substance when the particles in the sub

stance slow down
Physics
2 answers:
pochemuha4 years ago
4 0
Kinetic, thermal, and the temperature of the substance all decrease when the particles slow down.
sergeinik [125]4 years ago
4 0

Answer:

Average kinetic energy decreases

Thermal energy decreases

Temperature decreases

Explanation:

As the particles in a substance slow down then the kinetic energy of all the molecules will decreases.

As we know that kinetic energy is given as

KE = \frac{1}{2}mv^2

As we know that sum of kinetic energy of all the molecules is the molecules is known as internal thermal energy.

So here since kinetic energy decreases so internal thermal energy also decreases.

Now as we know that total internal thermal energy directly depends on temperature as

U = \frac{3}{2}nRT

so here as internal thermal energy decreases so its temperature also decreases.

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How far must the point charges q1 = +7.22 µc and q2 = -32.5 µc be separated for the electric potential energy of the system to b
Alik [6]
The formula that we wil be using is the formula for two charges q and Q separated by a distance r which is: U = kQq/r 
Where:
U = electric potential,
Q and q = point charges, and
r = the distance between the point charges.
 So we are looking for 'r', rearranging the formula would give us:
U*r = kQq
r = kQq/U -> this will be the formula that we will be using.
r = (9 x 10^9)*(7.22 x 10^-6)*(-32.5 x 10^-6) / -117 
r = .01805 m
8 0
4 years ago
In the generation of most anions, the energy change (kj/mol that _______ an electron is ________.
g100num [7]
Released                       taken in
<span>Anion are associated with exothermic process.</span>

7 0
4 years ago
Different regions of the galaxy tend to contain stars of different ages. Place labels for the ages of stars in the correct regio
Greeley [361]

Disk of dust and gas contains the new born stars and as well as young stars and the Halo region contains the old stars.

The different regions of a spiral galaxy like our Milky way tend to have characteristic populations of stars.

Halo: The halo tends to have older, red stars. In general, blue stars are larger but since they are also hotter, tend to run through their fuel faster and have shorter lives. Halo stars tend to be older stars, The halo is generally lacking in dust and low in metals.

Bulge: The outer Area of the bulge has mostly older red stars. The inner bulge has active star formation and has a mix of red and blue stars.

Disk: The disk has active star formation regions, so there are young blue stars in that region. Here are the stars that are both old stars and young stars. The blue stars are largely found on the edges of the spiral arms.

Thus disk with the dust clouds contains new and young stars. And halo region contains old stars.

#SPJ4

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6 0
2 years ago
When a net force of 17.0 newtons is applied to a dictionary placed on a frictionless table, it accelerates by 3.75 meters/second
vitfil [10]
F = ma
17 N = (3.75 m/s/s) m 
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5 0
3 years ago
Read 2 more answers
A beam of electrons moving in the x-direction enters a region where a uniform 208-G magnetic field points in the y-direction. Th
GREYUIT [131]

Answer:

1.26\cdot 10^7 m/s

Explanation:

When a charged particle moves perpendicularly to a magnetic field, the force it experiences is:

F=qvB

where

q is the charge

v is its velocity

B is the strength of the magnetic field

Moreover, the force acts in a direction perpendicular to the motion of the charge, so it acts as a centripetal force; therefore we can write:

qvB=m\frac{v^2}{r}

where

m is the mass of the particle

r is the radius of the orbit of the particle

The equation can be re-arranges as

v=\frac{qBr}{m}

where in this problem we have:

q=1.6\cdot 10^{-19}C is the magnitude of the charge of the electron

B=208 G=208\cdot 10^{-4}T is the strength of the magnetic field

The beam penetrates 3.45 mm into the field region: therefore, this is the radius of the orbit,

r=3.45 mm = 3.45\cdot 10^{-3} m

m=9.11\cdot 10^{-31} kg is the mass of the electron

So, the electron's speed is

v=\frac{(1.6\cdot 10^{-19})(208\cdot 10^{-4})(3.45\cdot 10^{-3})}{9.11\cdot 10^{-31}}=1.26\cdot 10^7 m/s

6 0
4 years ago
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