Answer:
2 molecules of water
Explanation:
In chemical reactions, molecules and compounds chemically combine to give products. This involves atoms combining by re-establishing bonding relationships.
4 hydrogen atoms is equivalent to 2 molecules of Hydrogen gas = H₂
2 oxygen atoms is the same as 1 oxygen molecule = O₂
This 2 molecules of hydrogen gas and 1 molecule of O₂ gas will combine to form 2 molecules of water chemically;
2H₂ + O₂ → 2H₂O
Answer:
The percent composition is 21% N, 6% H, 24% S and 49% O.
Explanation:
1st) The molar mass of (NH4)2SO4 is 132g/mol, and it represents the 100% of the mass composition.
In 1 mole of (NH4)2SO4, there are:
- 2 moles of N.
- 8 moles of H.
- 1 mole of S.
- 4 moles of O.
2nd) It is necessary to calculate the mass of each element, multiplying its molar mass by the number of moles:
- 2 moles of N (14g/mol) = 28g
- 8 moles of H (1g/mol) = 8g
- 1 mole of S (32g/mol) = 32g
- 4 moles of O (16g/mol) = 64g
3rd) With a mathematical rule of three we can calculate the percent composition of each element in the molecule of (NH4)2SO4:
![\begin{gathered} \text{ Nitrogen:} \\ 132g-100\% \\ 28g-x=\frac{28g*100\%}{132g} \\ x=21\% \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctext%7B%20Nitrogen%3A%7D%20%5C%5C%20132g-100%5C%25%20%5C%5C%2028g-x%3D%5Cfrac%7B28g%2A100%5C%25%7D%7B132g%7D%20%5C%5C%20x%3D21%5C%25%20%5Cend%7Bgathered%7D)
![\begin{gathered} \text{ Hydrogen:} \\ 132g-100\operatorname{\%} \\ 8g-x=\frac{8g*100\operatorname{\%}}{132g} \\ x=6\% \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctext%7B%20Hydrogen%3A%7D%20%5C%5C%20132g-100%5Coperatorname%7B%5C%25%7D%20%5C%5C%208g-x%3D%5Cfrac%7B8g%2A100%5Coperatorname%7B%5C%25%7D%7D%7B132g%7D%20%5C%5C%20x%3D6%5C%25%20%5Cend%7Bgathered%7D)
![\begin{gathered} \text{ Sulfur:} \\ 132g-100\operatorname{\%} \\ 32g-x=\frac{32g*100\operatorname{\%}}{132g} \\ x=24\% \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctext%7B%20Sulfur%3A%7D%20%5C%5C%20132g-100%5Coperatorname%7B%5C%25%7D%20%5C%5C%2032g-x%3D%5Cfrac%7B32g%2A100%5Coperatorname%7B%5C%25%7D%7D%7B132g%7D%20%5C%5C%20x%3D24%5C%25%20%5Cend%7Bgathered%7D)
![\begin{gathered} \text{ Oxygen:} \\ 100\%-21\%-6\%-24\%=49\% \\ \\ \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctext%7B%20Oxygen%3A%7D%20%5C%5C%20100%5C%25-21%5C%25-6%5C%25-24%5C%25%3D49%5C%25%20%5C%5C%20%20%5C%5C%20%20%5Cend%7Bgathered%7D)
In this case, we can calculate the percent composition of Oxygen by subtracting the other percentages, since the total must be 100%.
So, the percent composition is 21% N, 6% H, 24% S and 49% O.
Explanation:
When designing and conducting a scientific experiment then it is necessary to sequentially follows all the steps necessary for the experiment.
Also, it is required to identify independent variables, if any. On the other hand, it is required to address any confounding variables, so that it becomes mentioned the type or number of variables present.
Thus, we can conclude that when designing and conducting a scientific experiment:
- Identify the independent variable.
- Address any confounding variables.
Answer:
No, the pH scale can not be utilized for all types of acids known
Explanation:
The pH scale is a scale that shows the degree of acidity or alkalinity of a substance. The pH scale is graduated from 0-14. The pH scale is mostly applied to Arrhenius acids. Recall that in the Arrhenius definition, an acid produces hydrogen ion in solution while a base produces hydroxide ion in solution. Hence we could easily measure or calculate the pH and pOH of Arrhenius acids. Arrhenius acids apply mostly to acid-base discussion in Aqueous media.
Beyond aqueous media, we can still apply the Brownstead-Lowry and Lewis definitions for acid and base. Some of these substances to which we apply these other definitions of acid and base do not necessarily contain hydrogen or hydroxide ions hence the pH scale can not be utilized in discussing their acid-base properties, hence the answer.
Uh no I can’t help but, I hope you have a good day!