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hram777 [196]
4 years ago
12

As ocean waves get closer to the shore they slow down. This slowing causes them to bend and come in close to parallel with the s

hore. This is because shallow water and deep water can be thought of as two different media. This bending of a wave is the wave interaction known as
A) diffraction
B) interference
C) reflection
D) refraction
Physics
2 answers:
jonny [76]4 years ago
5 0

Answer:

i think it is D, hope this helps

iren [92.7K]4 years ago
4 0

The correct answer is D) refraction! Hope this helps!

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The table shows the percentage of carbon dioxide in the Earth’s atmosphere in the years 1800 and 2013. Calculate the difference
Natalka [10]

The difference in the mass of carbon dioxide in 500 kg of air in 2013 compared to 1800 is 0.06 Kg

<h3>Data obtained from the question</h3>
  • Year 1800 percent = 0.028%
  • Year 2013 percent = 0.040%
  • Mass of air = 500 Kg
  • Difference =?

<h3>How to determine the mass of CO₂ in 500 Kg in year 1800</h3>
  • Year 1800 percent = 0.028%
  • Mass of air = 500 Kg
  • Mass of CO₂ =?

Mass = percent × mass of air

Mass of CO₂ = 0.028% × 500

Mass of CO₂ = 0.14 Kg

<h3>How to determine the mass of CO₂ in 500 Kg in year 2013</h3>
  • Year 1800 percent = 0.040%
  • Mass of air = 500 Kg
  • Mass of CO₂ =?

Mass = percent × mass of air

Mass of CO₂ = 0.040% × 500

Mass of CO₂ = 0.2 Kg

<h3>How to determine the difference</h3>
  • Mass of CO₂ in year 1800 = 0.14 Kg
  • Mass of CO₂ in year 2013 = 0.2 Kg
  • Difference =?

Difference = mass in 2013 - mass in 1800

Difference = 0.2 - 0.14

Difference = 0.06 Kg

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The coefficient of linear expansion of iron is 1.0 × 10−5 per C◦ . The surface area of an iron cube, with an edge length of 5.0
Allushta [10]
The linear expansion of iron is a = 1× 10∧ -5 /°C
Length edge is 5cm
Initial surface area of cube A = 6L ∧²
 = 150cm∧²
The edge length of cube after being heated from 
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L = L[I +a dt] where the dt is = 60-10 = 50°C
5.0025cm
A surface area of the cube after heated is 
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= 150.1500375 cm∧²
The increased area is = A' -A = 0.15cm∧²
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