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sergejj [24]
3 years ago
13

At what speed is a particle's kinetic energy twice its rest energy?

Physics
1 answer:
bezimeni [28]3 years ago
5 0
The total energy of a particle is its rest energy plus the kinetic energy. Its formula is: Et= m^2/sqrt((1-v^2)/c^2))
The rest energy is equal to the product of mass and the square of light velocity: Er=mc^2.
When the kinetics energy is twice its rest energy this holds:
Et=Er
m^2/sqrt((1-v^2)/c^2))=<span>mc^2.
</span><span>sqrt((1-v^2)/c^2))=m/c^2
</span>=> v=sqrt(3/2)c
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if gas in a sealed container has a pressure of 50kpa at 300k what will the pressure be if the tempature rises to 360k
Zarrin [17]
The pressure law states that pressure is directly proportional to temperature.
p=kt where p is pressure, k is a constant, and t is temperature.

p=kt -- substitute
50000=k*300000
k=1/6
p=1/6*360000
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The pressure is 60kpa
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3 years ago
Can you be fluid overload and dehydrated at the same time
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5 0
3 years ago
a ship travels a port p and travels 30 km due north. then it changes course and travels 20 km in a direction  30° east of north
liq [111]

When we represent what is given to us on a coordinate plane, we have a figure as shown in the attachment.

To find the distance between P and R, we have to find the Net Displacement of the ship (brown arrow in the figure).

For that, we use the rules for Vector addition.

We see that the first displacement D_{1} = 30 km (blue arrow) is along the y-axis, but the second part of the ship's journey D_{2} = 20 km (red arrow) is at an angle with reference to y-axis.

So, we first find the components of the red arrow along X and Y.

Component of D_{2} along X-axis is given by  D_{2x}  = D_{2} Sin 30 = 10 km

Component of D_{2} along Y-axis is given by  D_{2y}  = D_{2} Cos 30 = 17.32 km

We now add all the vectors along X and along Y separately.

Net Displacement along X  D_{netX} = 10 km

Net Displacement along Y D_{netY} = 30 + 17.32 = 47.32 km

Now that we have the components of the net displacement along X and Y, we make use of Pythagorean Theorem to calculate the D_{net}

D_{net}  = \sqrt{D_{netX} ^{2} + D_{netY} ^{2}}

Therefore, [tex]D_{net} = 48.37 km.

Hence, the distance between the ports P and R is 48 km.

6 0
3 years ago
How is this formula ( Rt= r1 x r2 / r1 + r2) which is used to calculate total resistance of two parallel resistors found from th
Maru [420]

Explanation:

The total resistance used to calculate the total resistance of the two parallel resistor is given by :

R_t=\dfrac{r_1\times r_2}{r_1+r_2}

Taking reciprocal of the above equation.

\dfrac{1}{R_t}=\dfrac{r_1+r_2}{r_1\times r_2}

We can also write the above equation as :

\dfrac{1}{R_t}=\dfrac{r_1}{r_1\times r_2}+\dfrac{r_2}{r_1\times r_2}

On simplification of above equation,

\dfrac{1}{R_t}=\dfrac{1}{r_2}+\dfrac{1}{r_1}

or

\dfrac{1}{R_t}=\dfrac{1}{r_1}+\dfrac{1}{r_2}

Hence, proved.

4 0
3 years ago
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