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3 years ago

What is the weight of a clown triggerfish?

Physics

1 answer:

Ostrovityanka [42]3 years ago

3 0

There isn't a specific weight for it, but it can grow up to be a max of 3.3 feet in length.

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One way to measure g on another planet or moon by remote sensing is to measure how long it takes an object to fall a given dista

givi [52]

Answer:

a) $a=2.24m/s^{2}$

b) $v(t)=7.1m/s$

Explanation:

We use the kinematics equations:

$v(t)=v_{o}+g*t=g*t$ starting from rest

$y(t)=v_{o}t+1/2*a*t^{2}=1/2*a*t^{2$

$a=2*y/t^{2}=2*11.26/3.17^{2}=2.24m/s^{2}$

We find now the speed

$v(t)=a*t=2.24*3.17=7.1m/s$

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3 years ago

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zmey [24]

Answer:

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2 years ago

• A cable is suspended over a pulley. A 5.0 kg mass is attached to

Galina-37 [17]

Answer:

Tension= $\frac{20g}{3}$ (g=acceleration of gravity)

Explanation:

Given that,

A 5Kg and 10Kg are attached by a cable suspended over a pulley.

As 10Kg > 5Kg , the 10 kg mass accelerates down and the 5kg mass accelerates up, let it be a. Let the tension in the cable be T.

So, the equations of motion are

$10g-T = 10a$

$T-5g=5a$

Now adding them we get,

$5g=15a$

$a=\frac{g}{3}$

Substituting them back in the equation we get,

$10g-10(\frac{g}{3} ) = T$

$T= \frac{20g}{3}$

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3 years ago

When throwing curveballs in baseball, is it important to have air hit the ______ part of the ball.

Licemer1 [7]

Answer: A (smooth)

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3 years ago

Read 2 more answers

A coil of 160 turns and area 0.20 m2 is placed with its axis parallel to a magnetic field of initial magnitude 0.40 T. The magne

ser-zykov [4K]

Answer:

The rate at which power is generated in the coil is 10.24 Watts

Explanation:

Given;

number of turns of the coil, N = 160

area of the coil, A = 0.2 m²

magnitude of the magnetic field, B = 0.4 T

time for field change = 2 s

resistance of the coil, R = 16 Ω

The induced emf in the coil is calculated as;

emf = dΦ/dt

where;

Φ is magnetic flux = BA

emf = N (BA/dt)

emf = 160 (0.4T x 0.2 m²)/dt

emf = 12.8 V/s

The rate power is generated in the coil is calculated as;

P = V²/ R

P = (12.8²) / 16

P = 10.24 Watts

Therefore, the rate at which power is generated in the coil is 10.24 Watts

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3 years ago